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Lines Matching defs:pe

105 	u_char const *pe, *p;
132 	for (pe = pb + pat->patlen - 1; pb <= pe; pb++)
133 		d[*pb] = pe - pb;
138 	for (pb = pat->pat, pe = pb + pat->patlen - 1; pb < pe; pb++)
145 	for (pe = pat->pat + pat->patlen - 1, p = pe - 1; p >= pat->pat; p--)
146 		if (*p == *pe)
149 	/* *p is first leftward reoccurrence of *pe */
150 	pat->md2 = pe - p;