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tspeed.c revision 1.8
      1 /* This testcase is part of GDB, the GNU debugger.
      2 
      3    Copyright 2010-2019 Free Software Foundation, Inc.
      4 
      5    This program is free software; you can redistribute it and/or modify
      6    it under the terms of the GNU General Public License as published by
      7    the Free Software Foundation; either version 3 of the License, or
      8    (at your option) any later version.
      9 
     10    This program is distributed in the hope that it will be useful,
     11    but WITHOUT ANY WARRANTY; without even the implied warranty of
     12    MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
     13    GNU General Public License for more details.
     14 
     15    You should have received a copy of the GNU General Public License
     16    along with this program.  If not, see <http://www.gnu.org/licenses/>.  */
     17 
     18 /* This program tests tracepoint speed. It consists of two identical
     19    loops, which in normal execution will run for exactly the same
     20    amount of time. A tracepoint in the second loop will slow it down
     21    by some amount, and then the program will report the slowdown
     22    observed.  */
     23 
     24 /* While primarily designed for the testsuite, it can also be used
     25    for interactive testing.  */
     26 
     27 #include <stdio.h>
     28 #include <time.h>
     29 #include <sys/time.h>
     30 #include <sys/resource.h>
     31 #include <unistd.h>
     32 
     33 int trace_speed_test (void);
     34 
     35 /* We mark these globals as volatile so the speed-measuring loops
     36    don't get totally emptied out at high optimization levels.  */
     37 
     38 volatile int globfoo, globfoo2, globfoo3;
     39 
     40 volatile short globarr[80000];
     41 
     42 int init_iters = 10 * 1000;
     43 
     44 int iters;
     45 
     46 int max_iters = 1000 * 1000 * 1000;
     47 
     48 int numtps = 1;
     49 
     50 unsigned long long now2, now3, now4, now5;
     51 int total1, total2, idelta, mindelta, nsdelta;
     52 int nspertp = 0;
     53 
     54 /* Return CPU usage (both user and system - trap-based tracepoints use
     55    a bunch of system time).  */
     56 
     57 unsigned long long
     58 myclock ()
     59 {
     60   struct timeval tm;
     61   gettimeofday (&tm, NULL);
     62   return (((unsigned long long) tm.tv_sec) * 1000000) + tm.tv_usec;
     63 }
     64 
     65 int
     66 main(int argc, char **argv)
     67 {
     68   int problem;
     69 
     70   iters = init_iters;
     71 
     72   while (1)
     73     {
     74       numtps = 1;  /* set pre-run breakpoint here */
     75 
     76       /* Keep trying the speed test, with more iterations, until
     77 	 we get to a reasonable number.  */
     78       while (problem = trace_speed_test())
     79 	{
     80 	  /* If iteration isn't working, give up.  */
     81 	  if (iters > max_iters)
     82 	    {
     83 	      printf ("Gone over %d iterations, giving up\n", max_iters);
     84 	      break;
     85 	    }
     86 	  if (problem < 0)
     87 	    {
     88 	      printf ("Negative times, giving up\n");
     89 	      break;
     90 	    }
     91 
     92 	  iters *= 2;
     93 	  printf ("Doubled iterations to %d\n", iters);
     94 	}
     95 
     96       printf ("Tracepoint time is %d ns\n", nspertp);
     97 
     98       /* This is for the benefit of interactive testing and attaching,
     99 	 keeps the program from pegging the machine.  */
    100       sleep (1);  /* set post-run breakpoint here */
    101 
    102       /* Issue a little bit of output periodically, so we can see if
    103 	 program is alive or hung.  */
    104       printf ("%s keeping busy, clock=%llu\n", argv[0], myclock ());
    105     }
    106   return 0;
    107 }
    108 
    109 int
    110 trace_speed_test (void)
    111 {
    112   int i;
    113 
    114   /* Overall loop run time deltas under 1 ms are likely noise and
    115      should be ignored.  */
    116   mindelta = 1000;
    117 
    118   // The bodies of the two loops following must be identical.
    119 
    120   now2 = myclock ();
    121   globfoo2 = 1;
    122   for (i = 0; i < iters; ++i)
    123     {
    124       globfoo2 *= 45;
    125       globfoo2 += globfoo + globfoo3;
    126       globfoo2 *= globfoo + globfoo3;
    127       globfoo2 -= globarr[4] + globfoo3;
    128       globfoo2 *= globfoo + globfoo3;
    129       globfoo2 += globfoo + globfoo3;
    130     }
    131   now3 = myclock ();
    132   total1 = now3 - now2;
    133 
    134   now4 = myclock ();
    135   globfoo2 = 1;
    136   for (i = 0; i < iters; ++i)
    137     {
    138       globfoo2 *= 45;
    139       globfoo2 += globfoo + globfoo3;  /* set tracepoint here */
    140       globfoo2 *= globfoo + globfoo3;
    141       globfoo2 -= globarr[4] + globfoo3;
    142       globfoo2 *= globfoo + globfoo3;
    143       globfoo2 += globfoo + globfoo3;
    144     }
    145   now5 = myclock ();
    146   total2 = now5 - now4;
    147 
    148   /* Report on the test results.  */
    149 
    150   nspertp = 0;
    151 
    152   idelta = total2 - total1;
    153 
    154   printf ("Loops took %d usec and %d usec, delta is %d usec, %d iterations\n",
    155 	  total1, total2, idelta, iters);
    156 
    157   /* If the second loop seems to run faster, things are weird so give up.  */
    158   if (idelta < 0)
    159     return -1;
    160 
    161   if (idelta > mindelta
    162       /* Total test time should be between 15 and 30 seconds.  */
    163       && (total1 + total2) > (15 * 1000000)
    164       && (total1 + total2) < (30 * 1000000))
    165     {
    166       nsdelta = (((unsigned long long) idelta) * 1000) / iters;
    167       printf ("Second loop took %d ns longer per iter than first\n", nsdelta);
    168       nspertp = nsdelta / numtps;
    169       printf ("%d ns per tracepoint\n", nspertp);
    170       printf ("Base iteration time %d ns\n",
    171 	      ((int) (((unsigned long long) total1) * 1000) / iters));
    172       printf ("Total test time %d secs\n", ((int) ((now5 - now2) / 1000000)));
    173 
    174       /* Speed test ran with no problem.  */
    175       return 0;
    176     }
    177 
    178   /* The test run was too brief, or otherwise not useful.  */
    179   return 1;
    180 }
    181