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arithmetic.c revision 1.21
      1 /*	$NetBSD: arithmetic.c,v 1.21 2004/11/05 21:30:31 dsl Exp $	*/
      2 
      3 /*
      4  * Copyright (c) 1989, 1993
      5  *	The Regents of the University of California.  All rights reserved.
      6  *
      7  * This code is derived from software contributed to Berkeley by
      8  * Eamonn McManus of Trinity College Dublin.
      9  *
     10  * Redistribution and use in source and binary forms, with or without
     11  * modification, are permitted provided that the following conditions
     12  * are met:
     13  * 1. Redistributions of source code must retain the above copyright
     14  *    notice, this list of conditions and the following disclaimer.
     15  * 2. Redistributions in binary form must reproduce the above copyright
     16  *    notice, this list of conditions and the following disclaimer in the
     17  *    documentation and/or other materials provided with the distribution.
     18  * 3. Neither the name of the University nor the names of its contributors
     19  *    may be used to endorse or promote products derived from this software
     20  *    without specific prior written permission.
     21  *
     22  * THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND
     23  * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
     24  * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
     25  * ARE DISCLAIMED.  IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
     26  * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
     27  * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
     28  * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
     29  * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
     30  * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
     31  * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
     32  * SUCH DAMAGE.
     33  */
     34 
     35 #include <sys/cdefs.h>
     36 #ifndef lint
     37 __COPYRIGHT("@(#) Copyright (c) 1989, 1993\n\
     38 	The Regents of the University of California.  All rights reserved.\n");
     39 #endif /* not lint */
     40 
     41 #ifndef lint
     42 #if 0
     43 static char sccsid[] = "@(#)arithmetic.c	8.1 (Berkeley) 5/31/93";
     44 #else
     45 __RCSID("$NetBSD: arithmetic.c,v 1.21 2004/11/05 21:30:31 dsl Exp $");
     46 #endif
     47 #endif /* not lint */
     48 
     49 /*
     50  * By Eamonn McManus, Trinity College Dublin <emcmanus (at) cs.tcd.ie>.
     51  *
     52  * The operation of this program mimics that of the standard Unix game
     53  * `arithmetic'.  I've made it as close as I could manage without examining
     54  * the source code.  The principal differences are:
     55  *
     56  * The method of biasing towards numbers that had wrong answers in the past
     57  * is different; original `arithmetic' seems to retain the bias forever,
     58  * whereas this program lets the bias gradually decay as it is used.
     59  *
     60  * Original `arithmetic' delays for some period (3 seconds?) after printing
     61  * the score.  I saw no reason for this delay, so I scrapped it.
     62  *
     63  * There is no longer a limitation on the maximum range that can be supplied
     64  * to the program.  The original program required it to be less than 100.
     65  * Anomalous results may occur with this program if ranges big enough to
     66  * allow overflow are given.
     67  *
     68  * I have obviously not attempted to duplicate bugs in the original.  It
     69  * would go into an infinite loop if invoked as `arithmetic / 0'.  It also
     70  * did not recognise an EOF in its input, and would continue trying to read
     71  * after it.  It did not check that the input was a valid number, treating any
     72  * garbage as 0.  Finally, it did not flush stdout after printing its prompt,
     73  * so in the unlikely event that stdout was not a terminal, it would not work
     74  * properly.
     75  */
     76 
     77 #include <sys/types.h>
     78 #include <err.h>
     79 #include <ctype.h>
     80 #include <signal.h>
     81 #include <stdio.h>
     82 #include <stdlib.h>
     83 #include <string.h>
     84 #include <time.h>
     85 #include <unistd.h>
     86 
     87 int	getrandom(int, int, int);
     88 void	intr(int) __attribute__((__noreturn__));
     89 int	main(int, char *[]);
     90 int	opnum(int);
     91 void	penalise(int, int, int);
     92 int	problem(void);
     93 void	showstats(int);
     94 void	usage(void) __attribute__((__noreturn__));
     95 
     96 const char keylist[] = "+-x/";
     97 const char defaultkeys[] = "+-";
     98 const char *keys = defaultkeys;
     99 int nkeys = sizeof(defaultkeys) - 1;
    100 int rangemax = 10;
    101 int nright, nwrong;
    102 time_t qtime;
    103 #define	NQUESTS	20
    104 
    105 /*
    106  * Select keys from +-x/ to be asked addition, subtraction, multiplication,
    107  * and division problems.  More than one key may be given.  The default is
    108  * +-.  Specify a range to confine the operands to 0 - range.  Default upper
    109  * bound is 10.  After every NQUESTS questions, statistics on the performance
    110  * so far are printed.
    111  */
    112 int
    113 main(argc, argv)
    114 	int argc;
    115 	char **argv;
    116 {
    117 	int ch, cnt;
    118 
    119 	/* Revoke setgid privileges */
    120 	setgid(getgid());
    121 
    122 	while ((ch = getopt(argc, argv, "r:o:")) != -1)
    123 		switch(ch) {
    124 		case 'o': {
    125 			const char *p;
    126 
    127 			for (p = keys = optarg; *p; ++p)
    128 				if (!strchr(keylist, *p))
    129 					errx(1, "arithmetic: unknown key.");
    130 			nkeys = p - optarg;
    131 			break;
    132 		}
    133 		case 'r':
    134 			if ((rangemax = atoi(optarg)) <= 0)
    135 				errx(1, "arithmetic: invalid range.");
    136 			break;
    137 		case '?':
    138 		default:
    139 			usage();
    140 		}
    141 	if (argc -= optind)
    142 		usage();
    143 
    144 	/* Seed the random-number generator. */
    145 	srandom((int)time((time_t *)NULL));
    146 
    147 	(void)signal(SIGINT, intr);
    148 
    149 	/* Now ask the questions. */
    150 	for (;;) {
    151 		for (cnt = NQUESTS; cnt--;)
    152 			if (problem() == EOF)
    153 				exit(0);
    154 		showstats(0);
    155 	}
    156 	/* NOTREACHED */
    157 }
    158 
    159 /* Handle interrupt character.  Print score and exit. */
    160 void
    161 intr(dummy)
    162 	int dummy __attribute__((__unused__));
    163 {
    164 	showstats(1);
    165 	exit(0);
    166 }
    167 
    168 /* Print score.  Original `arithmetic' had a delay after printing it. */
    169 void
    170 showstats(bool_sigint)
    171 	int bool_sigint;
    172 {
    173 	if (nright + nwrong > 0) {
    174 		(void)printf("\n\nRights %d; Wrongs %d; Score %d%%",
    175 		    nright, nwrong, (int)(100L * nright / (nright + nwrong)));
    176 		if (nright > 0)
    177 	(void)printf("\nTotal time %ld seconds; %.1f seconds per problem\n\n",
    178 			    (long)qtime, (float)qtime / nright);
    179 	}
    180 	if(!bool_sigint) {
    181 		(void)printf("Press RETURN to continue...\n");
    182 		while(!getchar()) ;
    183 	}
    184 	(void)printf("\n");
    185 }
    186 
    187 /*
    188  * Pick a problem and ask it.  Keeps asking the same problem until supplied
    189  * with the correct answer, or until EOF or interrupt is typed.  Problems are
    190  * selected such that the right operand and either the left operand (for +, x)
    191  * or the correct result (for -, /) are in the range 0 to rangemax.  Each wrong
    192  * answer causes the numbers in the problem to be penalised, so that they are
    193  * more likely to appear in subsequent problems.
    194  */
    195 int
    196 problem()
    197 {
    198 	char *p;
    199 	time_t start, finish;
    200 	int left, op, right, result;
    201 	char line[80];
    202 
    203 	right = left = result = 0;
    204 	op = keys[random() % nkeys];
    205 	if (op != '/')
    206 		right = getrandom(rangemax + 1, op, 1);
    207 retry:
    208 	/* Get the operands. */
    209 	switch (op) {
    210 	case '+':
    211 		left = getrandom(rangemax + 1, op, 0);
    212 		result = left + right;
    213 		break;
    214 	case '-':
    215 		result = getrandom(rangemax + 1, op, 0);
    216 		left = right + result;
    217 		break;
    218 	case 'x':
    219 		left = getrandom(rangemax + 1, op, 0);
    220 		result = left * right;
    221 		break;
    222 	case '/':
    223 		right = getrandom(rangemax, op, 1) + 1;
    224 		result = getrandom(rangemax + 1, op, 0);
    225 		left = right * result + random() % right;
    226 		break;
    227 	}
    228 
    229 	/*
    230 	 * A very big maxrange could cause negative values to pop
    231 	 * up, owing to overflow.
    232 	 */
    233 	if (result < 0 || left < 0)
    234 		goto retry;
    235 
    236 	(void)printf("%d %c %d =   ", left, op, right);
    237 	(void)fflush(stdout);
    238 	(void)time(&start);
    239 
    240 	/*
    241 	 * Keep looping until the correct answer is given, or until EOF or
    242 	 * interrupt is typed.
    243 	 */
    244 	for (;;) {
    245 		if (!fgets(line, sizeof(line), stdin)) {
    246 			(void)printf("\n");
    247 			return(EOF);
    248 		}
    249 		for (p = line; *p && isspace((unsigned char)*p); ++p);
    250 		if (!isdigit((unsigned char)*p)) {
    251 			(void)printf("Please type a number.\n");
    252 			continue;
    253 		}
    254 		if (atoi(p) == result) {
    255 			(void)printf("Right!\n");
    256 			++nright;
    257 			break;
    258 		}
    259 		/* Wrong answer; penalise and ask again. */
    260 		(void)printf("What?\n");
    261 		++nwrong;
    262 		penalise(right, op, 1);
    263 		if (op == 'x' || op == '+')
    264 			penalise(left, op, 0);
    265 		else
    266 			penalise(result, op, 0);
    267 	}
    268 
    269 	/*
    270 	 * Accumulate the time taken.  Obviously rounding errors happen here;
    271 	 * however they should cancel out, because some of the time you are
    272 	 * charged for a partially elapsed second at the start, and some of
    273 	 * the time you are not charged for a partially elapsed second at the
    274 	 * end.
    275 	 */
    276 	(void)time(&finish);
    277 	qtime += finish - start;
    278 	return(0);
    279 }
    280 
    281 /*
    282  * Here is the code for accumulating penalties against the numbers for which
    283  * a wrong answer was given.  The right operand and either the left operand
    284  * (for +, x) or the result (for -, /) are stored in a list for the particular
    285  * operation, and each becomes more likely to appear again in that operation.
    286  * Initially, each number is charged a penalty of WRONGPENALTY, giving it that
    287  * many extra chances of appearing.  Each time it is selected because of this,
    288  * its penalty is decreased by one; it is removed when it reaches 0.
    289  *
    290  * The penalty[] array gives the sum of all penalties in the list for
    291  * each operation and each operand.  The penlist[] array has the lists of
    292  * penalties themselves.
    293  */
    294 
    295 int penalty[sizeof(keylist) - 1][2];
    296 struct penalty {
    297 	int value, penalty;	/* Penalised value and its penalty. */
    298 	struct penalty *next;
    299 } *penlist[sizeof(keylist) - 1][2];
    300 
    301 #define	WRONGPENALTY	5	/* Perhaps this should depend on maxrange. */
    302 
    303 /*
    304  * Add a penalty for the number `value' to the list for operation `op',
    305  * operand number `operand' (0 or 1).  If we run out of memory, we just
    306  * forget about the penalty (how likely is this, anyway?).
    307  */
    308 void
    309 penalise(value, op, operand)
    310 	int value, op, operand;
    311 {
    312 	struct penalty *p;
    313 
    314 	op = opnum(op);
    315 	if ((p = (struct penalty *)malloc((u_int)sizeof(*p))) == NULL)
    316 		return;
    317 	p->next = penlist[op][operand];
    318 	penlist[op][operand] = p;
    319 	penalty[op][operand] += p->penalty = WRONGPENALTY;
    320 	p->value = value;
    321 }
    322 
    323 /*
    324  * Select a random value from 0 to maxval - 1 for operand `operand' (0 or 1)
    325  * of operation `op'.  The random number we generate is either used directly
    326  * as a value, or represents a position in the penalty list.  If the latter,
    327  * we find the corresponding value and return that, decreasing its penalty.
    328  */
    329 int
    330 getrandom(maxval, op, operand)
    331 	int maxval, op, operand;
    332 {
    333 	int value;
    334 	struct penalty **pp, *p;
    335 
    336 	op = opnum(op);
    337 	value = random() % (maxval + penalty[op][operand]);
    338 
    339 	/*
    340 	 * 0 to maxval - 1 is a number to be used directly; bigger values
    341 	 * are positions to be located in the penalty list.
    342 	 */
    343 	if (value < maxval)
    344 		return(value);
    345 	value -= maxval;
    346 
    347 	/*
    348 	 * Find the penalty at position `value'; decrement its penalty and
    349 	 * delete it if it reaches 0; return the corresponding value.
    350 	 */
    351 	for (pp = &penlist[op][operand]; (p = *pp) != NULL; pp = &p->next) {
    352 		if (p->penalty > value) {
    353 			value = p->value;
    354 			penalty[op][operand]--;
    355 			if (--(p->penalty) <= 0) {
    356 				p = p->next;
    357 				(void)free((char *)*pp);
    358 				*pp = p;
    359 			}
    360 			return(value);
    361 		}
    362 		value -= p->penalty;
    363 	}
    364 	/*
    365 	 * We can only get here if the value from the penalty[] array doesn't
    366 	 * correspond to the actual sum of penalties in the list.  Provide an
    367 	 * obscure message.
    368 	 */
    369 	errx(1, "arithmetic: bug: inconsistent penalties.");
    370 	/* NOTREACHED */
    371 }
    372 
    373 /* Return an index for the character op, which is one of [+-x/]. */
    374 int
    375 opnum(op)
    376 	int op;
    377 {
    378 	char *p;
    379 
    380 	if (op == 0 || (p = strchr(keylist, op)) == NULL)
    381 		errx(1, "arithmetic: bug: op %c not in keylist %s",
    382 		    op, keylist);
    383 	return(p - keylist);
    384 }
    385 
    386 /* Print usage message and quit. */
    387 void
    388 usage()
    389 {
    390 	(void)fprintf(stderr, "Usage: %s [-o +-x/] [-r range]\n",
    391 		getprogname());
    392 	exit(1);
    393 }
    394