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arithmetic.c revision 1.8
      1 /*	$NetBSD: arithmetic.c,v 1.8 1997/10/10 11:49:44 lukem Exp $	*/
      2 
      3 /*
      4  * Copyright (c) 1989, 1993
      5  *	The Regents of the University of California.  All rights reserved.
      6  *
      7  * This code is derived from software contributed to Berkeley by
      8  * Eamonn McManus of Trinity College Dublin.
      9  *
     10  * Redistribution and use in source and binary forms, with or without
     11  * modification, are permitted provided that the following conditions
     12  * are met:
     13  * 1. Redistributions of source code must retain the above copyright
     14  *    notice, this list of conditions and the following disclaimer.
     15  * 2. Redistributions in binary form must reproduce the above copyright
     16  *    notice, this list of conditions and the following disclaimer in the
     17  *    documentation and/or other materials provided with the distribution.
     18  * 3. All advertising materials mentioning features or use of this software
     19  *    must display the following acknowledgement:
     20  *	This product includes software developed by the University of
     21  *	California, Berkeley and its contributors.
     22  * 4. Neither the name of the University nor the names of its contributors
     23  *    may be used to endorse or promote products derived from this software
     24  *    without specific prior written permission.
     25  *
     26  * THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND
     27  * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
     28  * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
     29  * ARE DISCLAIMED.  IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
     30  * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
     31  * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
     32  * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
     33  * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
     34  * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
     35  * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
     36  * SUCH DAMAGE.
     37  */
     38 
     39 #include <sys/cdefs.h>
     40 #ifndef lint
     41 __COPYRIGHT("@(#) Copyright (c) 1989, 1993\n\
     42 	The Regents of the University of California.  All rights reserved.\n");
     43 #endif /* not lint */
     44 
     45 #ifndef lint
     46 #if 0
     47 static char sccsid[] = "@(#)arithmetic.c	8.1 (Berkeley) 5/31/93";
     48 #else
     49 __RCSID("$NetBSD: arithmetic.c,v 1.8 1997/10/10 11:49:44 lukem Exp $");
     50 #endif
     51 #endif /* not lint */
     52 
     53 /*
     54  * By Eamonn McManus, Trinity College Dublin <emcmanus (at) cs.tcd.ie>.
     55  *
     56  * The operation of this program mimics that of the standard Unix game
     57  * `arithmetic'.  I've made it as close as I could manage without examining
     58  * the source code.  The principal differences are:
     59  *
     60  * The method of biasing towards numbers that had wrong answers in the past
     61  * is different; original `arithmetic' seems to retain the bias forever,
     62  * whereas this program lets the bias gradually decay as it is used.
     63  *
     64  * Original `arithmetic' delays for some period (3 seconds?) after printing
     65  * the score.  I saw no reason for this delay, so I scrapped it.
     66  *
     67  * There is no longer a limitation on the maximum range that can be supplied
     68  * to the program.  The original program required it to be less than 100.
     69  * Anomalous results may occur with this program if ranges big enough to
     70  * allow overflow are given.
     71  *
     72  * I have obviously not attempted to duplicate bugs in the original.  It
     73  * would go into an infinite loop if invoked as `arithmetic / 0'.  It also
     74  * did not recognise an EOF in its input, and would continue trying to read
     75  * after it.  It did not check that the input was a valid number, treating any
     76  * garbage as 0.  Finally, it did not flush stdout after printing its prompt,
     77  * so in the unlikely event that stdout was not a terminal, it would not work
     78  * properly.
     79  */
     80 
     81 #include <sys/types.h>
     82 #include <err.h>
     83 #include <ctype.h>
     84 #include <signal.h>
     85 #include <stdio.h>
     86 #include <stdlib.h>
     87 #include <string.h>
     88 #include <time.h>
     89 
     90 int	getrandom __P((int, int, int));
     91 void	intr __P((int));
     92 int	main __P((int, char *[]));
     93 int	opnum __P((int));
     94 void	penalise __P((int, int, int));
     95 int	problem __P((void));
     96 void	showstats __P((void));
     97 void	usage __P((void));
     98 
     99 char keylist[] = "+-x/";
    100 char defaultkeys[] = "+-";
    101 char *keys = defaultkeys;
    102 int nkeys = sizeof(defaultkeys) - 1;
    103 int rangemax = 10;
    104 int nright, nwrong;
    105 time_t qtime;
    106 #define	NQUESTS	20
    107 
    108 /*
    109  * Select keys from +-x/ to be asked addition, subtraction, multiplication,
    110  * and division problems.  More than one key may be given.  The default is
    111  * +-.  Specify a range to confine the operands to 0 - range.  Default upper
    112  * bound is 10.  After every NQUESTS questions, statistics on the performance
    113  * so far are printed.
    114  */
    115 int
    116 main(argc, argv)
    117 	int argc;
    118 	char **argv;
    119 {
    120 	extern char *optarg;
    121 	extern int optind;
    122 	int ch, cnt;
    123 
    124 	while ((ch = getopt(argc, argv, "r:o:")) != -1)
    125 		switch(ch) {
    126 		case 'o': {
    127 			char *p;
    128 
    129 			for (p = keys = optarg; *p; ++p)
    130 				if (!strchr(keylist, *p))
    131 					errx(1, "arithmetic: unknown key.");
    132 			nkeys = p - optarg;
    133 			break;
    134 		}
    135 		case 'r':
    136 			if ((rangemax = atoi(optarg)) <= 0)
    137 				errx(1, "arithmetic: invalid range.");
    138 			break;
    139 		case '?':
    140 		default:
    141 			usage();
    142 		}
    143 	if (argc -= optind)
    144 		usage();
    145 
    146 	/* Seed the random-number generator. */
    147 	srandom((int)time((time_t *)NULL));
    148 
    149 	(void)signal(SIGINT, intr);
    150 
    151 	/* Now ask the questions. */
    152 	for (;;) {
    153 		for (cnt = NQUESTS; cnt--;)
    154 			if (problem() == EOF)
    155 				exit(0);
    156 		showstats();
    157 	}
    158 	/* NOTREACHED */
    159 }
    160 
    161 /* Handle interrupt character.  Print score and exit. */
    162 void
    163 intr(dummy)
    164 	int dummy;
    165 {
    166 	showstats();
    167 	exit(0);
    168 }
    169 
    170 /* Print score.  Original `arithmetic' had a delay after printing it. */
    171 void
    172 showstats()
    173 {
    174 	if (nright + nwrong > 0) {
    175 		(void)printf("\n\nRights %d; Wrongs %d; Score %d%%",
    176 		    nright, nwrong, (int)(100L * nright / (nright + nwrong)));
    177 		if (nright > 0)
    178 	(void)printf("\nTotal time %ld seconds; %.1f seconds per problem\n\n",
    179 			    (long)qtime, (float)qtime / nright);
    180 	}
    181 	(void)printf("\n");
    182 }
    183 
    184 /*
    185  * Pick a problem and ask it.  Keeps asking the same problem until supplied
    186  * with the correct answer, or until EOF or interrupt is typed.  Problems are
    187  * selected such that the right operand and either the left operand (for +, x)
    188  * or the correct result (for -, /) are in the range 0 to rangemax.  Each wrong
    189  * answer causes the numbers in the problem to be penalised, so that they are
    190  * more likely to appear in subsequent problems.
    191  */
    192 int
    193 problem()
    194 {
    195 	char *p;
    196 	time_t start, finish;
    197 	int left, op, right, result;
    198 	char line[80];
    199 
    200 	left = result = 0;
    201 	op = keys[random() % nkeys];
    202 	if (op != '/')
    203 		right = getrandom(rangemax + 1, op, 1);
    204 retry:
    205 	/* Get the operands. */
    206 	switch (op) {
    207 	case '+':
    208 		left = getrandom(rangemax + 1, op, 0);
    209 		result = left + right;
    210 		break;
    211 	case '-':
    212 		result = getrandom(rangemax + 1, op, 0);
    213 		left = right + result;
    214 		break;
    215 	case 'x':
    216 		left = getrandom(rangemax + 1, op, 0);
    217 		result = left * right;
    218 		break;
    219 	case '/':
    220 		right = getrandom(rangemax, op, 1) + 1;
    221 		result = getrandom(rangemax + 1, op, 0);
    222 		left = right * result + random() % right;
    223 		break;
    224 	}
    225 
    226 	/*
    227 	 * A very big maxrange could cause negative values to pop
    228 	 * up, owing to overflow.
    229 	 */
    230 	if (result < 0 || left < 0)
    231 		goto retry;
    232 
    233 	(void)printf("%d %c %d =   ", left, op, right);
    234 	(void)fflush(stdout);
    235 	(void)time(&start);
    236 
    237 	/*
    238 	 * Keep looping until the correct answer is given, or until EOF or
    239 	 * interrupt is typed.
    240 	 */
    241 	for (;;) {
    242 		if (!fgets(line, sizeof(line), stdin)) {
    243 			(void)printf("\n");
    244 			return(EOF);
    245 		}
    246 		for (p = line; *p && isspace(*p); ++p);
    247 		if (!isdigit(*p)) {
    248 			(void)printf("Please type a number.\n");
    249 			continue;
    250 		}
    251 		if (atoi(p) == result) {
    252 			(void)printf("Right!\n");
    253 			++nright;
    254 			break;
    255 		}
    256 		/* Wrong answer; penalise and ask again. */
    257 		(void)printf("What?\n");
    258 		++nwrong;
    259 		penalise(right, op, 1);
    260 		if (op == 'x' || op == '+')
    261 			penalise(left, op, 0);
    262 		else
    263 			penalise(result, op, 0);
    264 	}
    265 
    266 	/*
    267 	 * Accumulate the time taken.  Obviously rounding errors happen here;
    268 	 * however they should cancel out, because some of the time you are
    269 	 * charged for a partially elapsed second at the start, and some of
    270 	 * the time you are not charged for a partially elapsed second at the
    271 	 * end.
    272 	 */
    273 	(void)time(&finish);
    274 	qtime += finish - start;
    275 	return(0);
    276 }
    277 
    278 /*
    279  * Here is the code for accumulating penalties against the numbers for which
    280  * a wrong answer was given.  The right operand and either the left operand
    281  * (for +, x) or the result (for -, /) are stored in a list for the particular
    282  * operation, and each becomes more likely to appear again in that operation.
    283  * Initially, each number is charged a penalty of WRONGPENALTY, giving it that
    284  * many extra chances of appearing.  Each time it is selected because of this,
    285  * its penalty is decreased by one; it is removed when it reaches 0.
    286  *
    287  * The penalty[] array gives the sum of all penalties in the list for
    288  * each operation and each operand.  The penlist[] array has the lists of
    289  * penalties themselves.
    290  */
    291 
    292 int penalty[sizeof(keylist) - 1][2];
    293 struct penalty {
    294 	int value, penalty;	/* Penalised value and its penalty. */
    295 	struct penalty *next;
    296 } *penlist[sizeof(keylist) - 1][2];
    297 
    298 #define	WRONGPENALTY	5	/* Perhaps this should depend on maxrange. */
    299 
    300 /*
    301  * Add a penalty for the number `value' to the list for operation `op',
    302  * operand number `operand' (0 or 1).  If we run out of memory, we just
    303  * forget about the penalty (how likely is this, anyway?).
    304  */
    305 void
    306 penalise(value, op, operand)
    307 	int value, op, operand;
    308 {
    309 	struct penalty *p;
    310 
    311 	op = opnum(op);
    312 	if ((p = (struct penalty *)malloc((u_int)sizeof(*p))) == NULL)
    313 		return;
    314 	p->next = penlist[op][operand];
    315 	penlist[op][operand] = p;
    316 	penalty[op][operand] += p->penalty = WRONGPENALTY;
    317 	p->value = value;
    318 }
    319 
    320 /*
    321  * Select a random value from 0 to maxval - 1 for operand `operand' (0 or 1)
    322  * of operation `op'.  The random number we generate is either used directly
    323  * as a value, or represents a position in the penalty list.  If the latter,
    324  * we find the corresponding value and return that, decreasing its penalty.
    325  */
    326 int
    327 getrandom(maxval, op, operand)
    328 	int maxval, op, operand;
    329 {
    330 	int value;
    331 	struct penalty **pp, *p;
    332 
    333 	op = opnum(op);
    334 	value = random() % (maxval + penalty[op][operand]);
    335 
    336 	/*
    337 	 * 0 to maxval - 1 is a number to be used directly; bigger values
    338 	 * are positions to be located in the penalty list.
    339 	 */
    340 	if (value < maxval)
    341 		return(value);
    342 	value -= maxval;
    343 
    344 	/*
    345 	 * Find the penalty at position `value'; decrement its penalty and
    346 	 * delete it if it reaches 0; return the corresponding value.
    347 	 */
    348 	for (pp = &penlist[op][operand]; (p = *pp) != NULL; pp = &p->next) {
    349 		if (p->penalty > value) {
    350 			value = p->value;
    351 			penalty[op][operand]--;
    352 			if (--(p->penalty) <= 0) {
    353 				p = p->next;
    354 				(void)free((char *)*pp);
    355 				*pp = p;
    356 			}
    357 			return(value);
    358 		}
    359 		value -= p->penalty;
    360 	}
    361 	/*
    362 	 * We can only get here if the value from the penalty[] array doesn't
    363 	 * correspond to the actual sum of penalties in the list.  Provide an
    364 	 * obscure message.
    365 	 */
    366 	errx(1, "arithmetic: bug: inconsistent penalties.");
    367 	/* NOTREACHED */
    368 }
    369 
    370 /* Return an index for the character op, which is one of [+-x/]. */
    371 int
    372 opnum(op)
    373 	int op;
    374 {
    375 	char *p;
    376 
    377 	if (op == 0 || (p = strchr(keylist, op)) == NULL)
    378 		errx(1, "arithmetic: bug: op %c not in keylist %s",
    379 		    op, keylist);
    380 	return(p - keylist);
    381 }
    382 
    383 /* Print usage message and quit. */
    384 void
    385 usage()
    386 {
    387 	extern char *__progname;	/* from crt0.o */
    388 
    389 	(void)fprintf(stderr, "usage: %s [-o +-x/] [-r range]\n",
    390 		__progname);
    391 	exit(1);
    392 }
    393