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parse.c revision 1.9
      1 /*	$NetBSD: parse.c,v 1.9 2000/09/22 08:19:21 jsm Exp $	*/
      2 
      3 /*
      4  * Copyright (c) 1983, 1993
      5  *	The Regents of the University of California.  All rights reserved.
      6  *
      7  * Redistribution and use in source and binary forms, with or without
      8  * modification, are permitted provided that the following conditions
      9  * are met:
     10  * 1. Redistributions of source code must retain the above copyright
     11  *    notice, this list of conditions and the following disclaimer.
     12  * 2. Redistributions in binary form must reproduce the above copyright
     13  *    notice, this list of conditions and the following disclaimer in the
     14  *    documentation and/or other materials provided with the distribution.
     15  * 3. All advertising materials mentioning features or use of this software
     16  *    must display the following acknowledgement:
     17  *	This product includes software developed by the University of
     18  *	California, Berkeley and its contributors.
     19  * 4. Neither the name of the University nor the names of its contributors
     20  *    may be used to endorse or promote products derived from this software
     21  *    without specific prior written permission.
     22  *
     23  * THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND
     24  * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
     25  * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
     26  * ARE DISCLAIMED.  IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
     27  * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
     28  * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
     29  * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
     30  * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
     31  * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
     32  * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
     33  * SUCH DAMAGE.
     34  */
     35 
     36 #include <sys/cdefs.h>
     37 #ifndef lint
     38 #if 0
     39 static char sccsid[] = "@(#)parse.c	8.2 (Berkeley) 4/28/95";
     40 #else
     41 __RCSID("$NetBSD: parse.c,v 1.9 2000/09/22 08:19:21 jsm Exp $");
     42 #endif
     43 #endif				/* not lint */
     44 
     45 #include "extern.h"
     46 
     47 void
     48 wordinit()
     49 {
     50 	struct wlist *w;
     51 
     52 	for (w = wlist; w->string; w++)
     53 		install(w);
     54 }
     55 
     56 int
     57 hash(s)
     58 	const char   *s;
     59 {
     60 	int     hashval = 0;
     61 
     62 	while (*s) {
     63 		hashval += *s++;
     64 		hashval *= HASHMUL;
     65 		hashval &= HASHMASK;
     66 	}
     67 	return hashval;
     68 }
     69 
     70 struct wlist *
     71 lookup(s)
     72 	const char   *s;
     73 {
     74 	struct wlist *wp;
     75 
     76 	for (wp = hashtab[hash(s)]; wp != NULL; wp = wp->next)
     77 		if (*s == *wp->string && strcmp(s, wp->string) == 0)
     78 			return wp;
     79 	return NULL;
     80 }
     81 
     82 void
     83 install(wp)
     84 	struct wlist *wp;
     85 {
     86 	int     hashval;
     87 
     88 	if (lookup(wp->string) == NULL) {
     89 		hashval = hash(wp->string);
     90 		wp->next = hashtab[hashval];
     91 		hashtab[hashval] = wp;
     92 	} else
     93 		printf("Multiply defined %s.\n", wp->string);
     94 }
     95 
     96 void
     97 parse()
     98 {
     99 	struct wlist *wp;
    100 	int     n;
    101 	int     flag;
    102 
    103 	wordnumber = 0;		/* for cypher */
    104 	for (n = 0; n <= wordcount; n++) {
    105 		if ((wp = lookup(words[n])) == NULL) {
    106 			wordvalue[n] = -1;
    107 			wordtype[n] = -1;
    108 		} else {
    109 			wordvalue[n] = wp->value;
    110 			wordtype[n] = wp->article;
    111 		}
    112 	}
    113 	/* We never use adjectives for anything, so yank them all. */
    114 	for (n = 1; n < wordcount; n++)
    115 		if (wordtype[n] == ADJS) {
    116 			int i;
    117 			for (i = n + 1; i < wordcount; i++) {
    118 				wordtype[i - 1] = wordtype[i];
    119 				wordvalue[i - 1] = wordvalue[i];
    120 				strcpy(words[i - 1], words[i]);
    121 			}
    122 			wordcount--;
    123 		}
    124 	/* Don't let a comma mean AND if followed by a verb. */
    125 	for (n = 0; n < wordcount; n++)
    126 		if (wordvalue[n] == AND && words[n][0] == ','
    127 		    && wordtype[n + 1] == VERB) {
    128 			wordvalue[n] = -1;
    129 			wordtype[n] = -1;
    130 		}
    131 	/* Trim "AND AND" which can happen naturally at the end of a
    132 	 * comma-delimited list.
    133 	 */
    134 	for (n = 1; n < wordcount; n++)
    135 		if (wordvalue[n - 1] == AND && wordvalue[n] == AND) {
    136 			int i;
    137 			for (i = n + 1; i < wordcount; i++) {
    138 				wordtype[i - 1] = wordtype[i];
    139 				wordvalue[i - 1] = wordvalue[i];
    140 				strcpy(words[i - 1], words[i]);
    141 			}
    142 			wordcount--;
    143 		}
    144 
    145 	/* If there is a sequence (NOUN | OBJECT) AND EVERYTHING
    146 	 * then move all the EVERYTHINGs to the beginning, since that's where
    147 	 * they're expected.  We can't get rid of the NOUNs and OBJECTs in
    148 	 * case they aren't in EVERYTHING (i.e. not here or nonexistant).
    149 	 */
    150 	flag = 1;
    151 	while (flag) {
    152 		flag = 0;
    153 		for (n = 1; n < wordcount; n++)
    154 			if ((wordtype[n - 1] == NOUNS || wordtype[n - 1] == OBJECT) &&
    155 			    wordvalue[n] == AND && wordvalue[n + 1] == EVERYTHING) {
    156 				char tmpword[WORDLEN];
    157 				wordvalue[n + 1] = wordvalue[n - 1];
    158 				wordvalue[n - 1] = EVERYTHING;
    159 				wordtype[n + 1] = wordtype[n - 1];
    160 				wordtype[n - 1] = OBJECT;
    161 				strcpy(tmpword, words[n - 1]);
    162 				strcpy(words[n - 1], words[n + 1]);
    163 				strcpy(words[n + 1], tmpword);
    164 				flag = 1;
    165 		}
    166 		/* And trim EVERYTHING AND EVERYTHING. */
    167 		for (n = 1; n < wordcount; n++)
    168 			if (wordvalue[n - 1] == EVERYTHING &&
    169 			    wordvalue[n] == AND && wordvalue[n + 1] == EVERYTHING) {
    170 				int i;
    171 				for (i = n + 1; i < wordcount; i++) {
    172 					wordtype[i - 1] = wordtype[i + 1];
    173 					wordvalue[i - 1] = wordvalue[i + 1];
    174 					strcpy(words[i - 1], words[i + 1]);
    175 				}
    176 				wordcount--;
    177 				wordcount--;
    178 				flag = 1;
    179 			}
    180 	}
    181 }
    182