Home | History | Annotate | Line # | Download | only in fpe
fpu_rem.c revision 1.4
      1 /*	$NetBSD: fpu_rem.c,v 1.4 1999/05/30 20:17:48 briggs Exp $	*/
      2 
      3 /*
      4  * Copyright (c) 1995  Ken Nakata
      5  *	All rights reserved.
      6  *
      7  * Redistribution and use in source and binary forms, with or without
      8  * modification, are permitted provided that the following conditions
      9  * are met:
     10  * 1. Redistributions of source code must retain the above copyright
     11  *    notice, this list of conditions and the following disclaimer.
     12  * 2. Redistributions in binary form must reproduce the above copyright
     13  *    notice, this list of conditions and the following disclaimer in the
     14  *    documentation and/or other materials provided with the distribution.
     15  * 3. Neither the name of the author nor the names of its contributors
     16  *    may be used to endorse or promote products derived from this software
     17  *    without specific prior written permission.
     18  *
     19  * THIS SOFTWARE IS PROVIDED BY THE AUTHOR AND CONTRIBUTORS ``AS IS'' AND
     20  * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
     21  * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
     22  * ARE DISCLAIMED.  IN NO EVENT SHALL THE AUTHOR OR CONTRIBUTORS BE LIABLE
     23  * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
     24  * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
     25  * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
     26  * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
     27  * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
     28  * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
     29  * SUCH DAMAGE.
     30  *
     31  *	@(#)fpu_rem.c	10/24/95
     32  */
     33 
     34 #include <sys/types.h>
     35 #include <sys/signal.h>
     36 #include <machine/frame.h>
     37 
     38 #include "fpu_emulate.h"
     39 
     40 /*
     41  *       ALGORITHM
     42  *
     43  *       Step 1.  Save and strip signs of X and Y: signX := sign(X),
     44  *                signY := sign(Y), X := *X*, Y := *Y*,
     45  *                signQ := signX EOR signY. Record whether MOD or REM
     46  *                is requested.
     47  *
     48  *       Step 2.  Set L := expo(X)-expo(Y), k := 0, Q := 0.
     49  *                If (L < 0) then
     50  *                   R := X, go to Step 4.
     51  *                else
     52  *                   R := 2^(-L)X, j := L.
     53  *                endif
     54  *
     55  *       Step 3.  Perform MOD(X,Y)
     56  *            3.1 If R = Y, go to Step 9.
     57  *            3.2 If R > Y, then { R := R - Y, Q := Q + 1}
     58  *            3.3 If j = 0, go to Step 4.
     59  *            3.4 k := k + 1, j := j - 1, Q := 2Q, R := 2R. Go to
     60  *                Step 3.1.
     61  *
     62  *       Step 4.  At this point, R = X - QY = MOD(X,Y). Set
     63  *                Last_Subtract := false (used in Step 7 below). If
     64  *                MOD is requested, go to Step 6.
     65  *
     66  *       Step 5.  R = MOD(X,Y), but REM(X,Y) is requested.
     67  *            5.1 If R < Y/2, then R = MOD(X,Y) = REM(X,Y). Go to
     68  *                Step 6.
     69  *            5.2 If R > Y/2, then { set Last_Subtract := true,
     70  *                Q := Q + 1, Y := signY*Y }. Go to Step 6.
     71  *            5.3 This is the tricky case of R = Y/2. If Q is odd,
     72  *                then { Q := Q + 1, signX := -signX }.
     73  *
     74  *       Step 6.  R := signX*R.
     75  *
     76  *       Step 7.  If Last_Subtract = true, R := R - Y.
     77  *
     78  *       Step 8.  Return signQ, last 7 bits of Q, and R as required.
     79  *
     80  *       Step 9.  At this point, R = 2^(-j)*X - Q Y = Y. Thus,
     81  *                X = 2^(j)*(Q+1)Y. set Q := 2^(j)*(Q+1),
     82  *                R := 0. Return signQ, last 7 bits of Q, and R.
     83  */
     84 
     85 static struct fpn * __fpu_modrem __P((struct fpemu *fe, int modrem));
     86 
     87 static struct fpn *
     88 __fpu_modrem(fe, modrem)
     89      struct fpemu *fe;
     90      int modrem;
     91 {
     92     static struct fpn X, Y;
     93     struct fpn *x, *y, *r;
     94     u_int signX, signY, signQ;
     95     int j, k, l, q;
     96     int Last_Subtract;
     97 
     98     CPYFPN(&X, &fe->fe_f1);
     99     CPYFPN(&Y, &fe->fe_f2);
    100     x = &X;
    101     y = &Y;
    102     r = &fe->fe_f2;
    103 
    104     /*
    105      * Step 1
    106      */
    107     signX = x->fp_sign;
    108     signY = y->fp_sign;
    109     signQ = (signX ^ signY);
    110     x->fp_sign = y->fp_sign = 0;
    111 
    112     /*
    113      * Step 2
    114      */
    115     l = x->fp_exp - y->fp_exp;
    116     k = 0;
    117     q = 0;
    118     if (l >= 0) {
    119 	CPYFPN(r, x);
    120 	r->fp_exp -= l;
    121 	j = l;
    122 
    123 	/*
    124 	 * Step 3
    125 	 */
    126 	while (y->fp_exp != r->fp_exp || y->fp_mant[0] != r->fp_mant[0] ||
    127 	       y->fp_mant[1] != r->fp_mant[1] ||
    128 	       y->fp_mant[2] != r->fp_mant[2]) {
    129 
    130 	    /* Step 3.2 */
    131 	    if (y->fp_exp < r->fp_exp || y->fp_mant[0] < r->fp_mant[0] ||
    132 		y->fp_mant[1] < r->fp_mant[1] ||
    133 		y->fp_mant[2] < r->fp_mant[2]) {
    134 		CPYFPN(&fe->fe_f1, r);
    135 		CPYFPN(&fe->fe_f2, y);
    136 		fe->fe_f2.fp_sign = 1;
    137 		r = fpu_add(fe);
    138 		q++;
    139 	    }
    140 
    141 	    /* Step 3.3 */
    142 	    if (j == 0)
    143 		goto Step4;
    144 
    145 	    /* Step 3.4 */
    146 	    k++;
    147 	    j--;
    148 	    q += q;
    149 	    r->fp_exp++;
    150 	}
    151 	/* Step 9 */
    152 	goto Step9;
    153     }
    154  Step4:
    155     Last_Subtract = 0;
    156     if (modrem == 0)
    157 	goto Step6;
    158 
    159     /*
    160      * Step 5
    161      */
    162     /* Step 5.1 */
    163     if (r->fp_exp + 1 < y->fp_exp ||
    164 	(r->fp_exp + 1 == y->fp_exp &&
    165 	 (r->fp_mant[0] < y->fp_mant[0] || r->fp_mant[1] < y->fp_mant[1] ||
    166 	  r->fp_mant[2] < y->fp_mant[2])))
    167 	/* if r < y/2 */
    168 	goto Step6;
    169     /* Step 5.2 */
    170     if (r->fp_exp + 1 != y->fp_exp ||
    171 	r->fp_mant[0] != y->fp_mant[0] || r->fp_mant[1] != y->fp_mant[1] ||
    172 	r->fp_mant[2] != y->fp_mant[2]) {
    173 	/* if (!(r < y/2) && !(r == y/2)) */
    174 	Last_Subtract = 1;
    175 	q++;
    176 	y->fp_sign = signY;
    177     } else {
    178 	/* Step 5.3 */
    179 	/* r == y/2 */
    180 	if (q % 2) {
    181 	    q++;
    182 	    signX = !signX;
    183 	}
    184     }
    185 
    186  Step6:
    187     r->fp_sign = signX;
    188 
    189     /*
    190      * Step 7
    191      */
    192     if (Last_Subtract) {
    193 	CPYFPN(&fe->fe_f1, r);
    194 	CPYFPN(&fe->fe_f2, y);
    195 	fe->fe_f2.fp_sign = !y->fp_sign;
    196 	r = fpu_add(fe);
    197     }
    198     /*
    199      * Step 8
    200      */
    201     q &= 0x7f;
    202     q |= (signQ << 7);
    203     fe->fe_fpframe->fpf_fpsr =
    204 	fe->fe_fpsr =
    205 	    (fe->fe_fpsr & ~FPSR_QTT) | (q << 16);
    206     return r;
    207 
    208  Step9:
    209     fe->fe_f1.fp_class = FPC_ZERO;
    210     q++;
    211     q &= 0x7f;
    212     q |= (signQ << 7);
    213     fe->fe_fpframe->fpf_fpsr =
    214 	fe->fe_fpsr =
    215 	    (fe->fe_fpsr & ~FPSR_QTT) | (q << 16);
    216     return &fe->fe_f1;
    217 }
    218 
    219 struct fpn *
    220 fpu_rem(fe)
    221      struct fpemu *fe;
    222 {
    223   return __fpu_modrem(fe, 1);
    224 }
    225 
    226 struct fpn *
    227 fpu_mod(fe)
    228      struct fpemu *fe;
    229 {
    230   return __fpu_modrem(fe, 0);
    231 }
    232