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fpu_add.c revision 1.4
      1 /*	$NetBSD: fpu_add.c,v 1.4 2003/07/15 00:04:59 lukem Exp $ */
      2 
      3 /*
      4  * Copyright (c) 1992, 1993
      5  *	The Regents of the University of California.  All rights reserved.
      6  *
      7  * This software was developed by the Computer Systems Engineering group
      8  * at Lawrence Berkeley Laboratory under DARPA contract BG 91-66 and
      9  * contributed to Berkeley.
     10  *
     11  * All advertising materials mentioning features or use of this software
     12  * must display the following acknowledgement:
     13  *	This product includes software developed by the University of
     14  *	California, Lawrence Berkeley Laboratory.
     15  *
     16  * Redistribution and use in source and binary forms, with or without
     17  * modification, are permitted provided that the following conditions
     18  * are met:
     19  * 1. Redistributions of source code must retain the above copyright
     20  *    notice, this list of conditions and the following disclaimer.
     21  * 2. Redistributions in binary form must reproduce the above copyright
     22  *    notice, this list of conditions and the following disclaimer in the
     23  *    documentation and/or other materials provided with the distribution.
     24  * 3. All advertising materials mentioning features or use of this software
     25  *    must display the following acknowledgement:
     26  *	This product includes software developed by the University of
     27  *	California, Berkeley and its contributors.
     28  * 4. Neither the name of the University nor the names of its contributors
     29  *    may be used to endorse or promote products derived from this software
     30  *    without specific prior written permission.
     31  *
     32  * THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND
     33  * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
     34  * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
     35  * ARE DISCLAIMED.  IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
     36  * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
     37  * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
     38  * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
     39  * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
     40  * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
     41  * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
     42  * SUCH DAMAGE.
     43  *
     44  *	@(#)fpu_add.c	8.1 (Berkeley) 6/11/93
     45  */
     46 
     47 /*
     48  * Perform an FPU add (return x + y).
     49  *
     50  * To subtract, negate y and call add.
     51  */
     52 
     53 #include <sys/cdefs.h>
     54 __KERNEL_RCSID(0, "$NetBSD: fpu_add.c,v 1.4 2003/07/15 00:04:59 lukem Exp $");
     55 
     56 #include <sys/types.h>
     57 #ifdef DIAGNOSTIC
     58 #include <sys/systm.h>
     59 #endif
     60 
     61 #include <machine/reg.h>
     62 #include <machine/instr.h>
     63 
     64 #include <sparc/fpu/fpu_arith.h>
     65 #include <sparc/fpu/fpu_emu.h>
     66 #include <sparc/fpu/fpu_extern.h>
     67 
     68 struct fpn *
     69 fpu_add(fe)
     70 	register struct fpemu *fe;
     71 {
     72 	register struct fpn *x = &fe->fe_f1, *y = &fe->fe_f2, *r;
     73 	register u_int r0, r1, r2, r3;
     74 	register int rd;
     75 
     76 	/*
     77 	 * Put the `heavier' operand on the right (see fpu_emu.h).
     78 	 * Then we will have one of the following cases, taken in the
     79 	 * following order:
     80 	 *
     81 	 *  - y = NaN.  Implied: if only one is a signalling NaN, y is.
     82 	 *	The result is y.
     83 	 *  - y = Inf.  Implied: x != NaN (is 0, number, or Inf: the NaN
     84 	 *    case was taken care of earlier).
     85 	 *	If x = -y, the result is NaN.  Otherwise the result
     86 	 *	is y (an Inf of whichever sign).
     87 	 *  - y is 0.  Implied: x = 0.
     88 	 *	If x and y differ in sign (one positive, one negative),
     89 	 *	the result is +0 except when rounding to -Inf.  If same:
     90 	 *	+0 + +0 = +0; -0 + -0 = -0.
     91 	 *  - x is 0.  Implied: y != 0.
     92 	 *	Result is y.
     93 	 *  - other.  Implied: both x and y are numbers.
     94 	 *	Do addition a la Hennessey & Patterson.
     95 	 */
     96 	ORDER(x, y);
     97 	if (ISNAN(y))
     98 		return (y);
     99 	if (ISINF(y)) {
    100 		if (ISINF(x) && x->fp_sign != y->fp_sign)
    101 			return (fpu_newnan(fe));
    102 		return (y);
    103 	}
    104 	rd = ((fe->fe_fsr >> FSR_RD_SHIFT) & FSR_RD_MASK);
    105 	if (ISZERO(y)) {
    106 		if (rd != FSR_RD_RM)	/* only -0 + -0 gives -0 */
    107 			y->fp_sign &= x->fp_sign;
    108 		else			/* any -0 operand gives -0 */
    109 			y->fp_sign |= x->fp_sign;
    110 		return (y);
    111 	}
    112 	if (ISZERO(x))
    113 		return (y);
    114 	/*
    115 	 * We really have two numbers to add, although their signs may
    116 	 * differ.  Make the exponents match, by shifting the smaller
    117 	 * number right (e.g., 1.011 => 0.1011) and increasing its
    118 	 * exponent (2^3 => 2^4).  Note that we do not alter the exponents
    119 	 * of x and y here.
    120 	 */
    121 	r = &fe->fe_f3;
    122 	r->fp_class = FPC_NUM;
    123 	if (x->fp_exp == y->fp_exp) {
    124 		r->fp_exp = x->fp_exp;
    125 		r->fp_sticky = 0;
    126 	} else {
    127 		if (x->fp_exp < y->fp_exp) {
    128 			/*
    129 			 * Try to avoid subtract case iii (see below).
    130 			 * This also guarantees that x->fp_sticky = 0.
    131 			 */
    132 			SWAP(x, y);
    133 		}
    134 		/* now x->fp_exp > y->fp_exp */
    135 		r->fp_exp = x->fp_exp;
    136 		r->fp_sticky = fpu_shr(y, x->fp_exp - y->fp_exp);
    137 	}
    138 	r->fp_sign = x->fp_sign;
    139 	if (x->fp_sign == y->fp_sign) {
    140 		FPU_DECL_CARRY
    141 
    142 		/*
    143 		 * The signs match, so we simply add the numbers.  The result
    144 		 * may be `supernormal' (as big as 1.111...1 + 1.111...1, or
    145 		 * 11.111...0).  If so, a single bit shift-right will fix it
    146 		 * (but remember to adjust the exponent).
    147 		 */
    148 		/* r->fp_mant = x->fp_mant + y->fp_mant */
    149 		FPU_ADDS(r->fp_mant[3], x->fp_mant[3], y->fp_mant[3]);
    150 		FPU_ADDCS(r->fp_mant[2], x->fp_mant[2], y->fp_mant[2]);
    151 		FPU_ADDCS(r->fp_mant[1], x->fp_mant[1], y->fp_mant[1]);
    152 		FPU_ADDC(r0, x->fp_mant[0], y->fp_mant[0]);
    153 		if ((r->fp_mant[0] = r0) >= FP_2) {
    154 			(void) fpu_shr(r, 1);
    155 			r->fp_exp++;
    156 		}
    157 	} else {
    158 		FPU_DECL_CARRY
    159 
    160 		/*
    161 		 * The signs differ, so things are rather more difficult.
    162 		 * H&P would have us negate the negative operand and add;
    163 		 * this is the same as subtracting the negative operand.
    164 		 * This is quite a headache.  Instead, we will subtract
    165 		 * y from x, regardless of whether y itself is the negative
    166 		 * operand.  When this is done one of three conditions will
    167 		 * hold, depending on the magnitudes of x and y:
    168 		 *   case i)   |x| > |y|.  The result is just x - y,
    169 		 *	with x's sign, but it may need to be normalized.
    170 		 *   case ii)  |x| = |y|.  The result is 0 (maybe -0)
    171 		 *	so must be fixed up.
    172 		 *   case iii) |x| < |y|.  We goofed; the result should
    173 		 *	be (y - x), with the same sign as y.
    174 		 * We could compare |x| and |y| here and avoid case iii,
    175 		 * but that would take just as much work as the subtract.
    176 		 * We can tell case iii has occurred by an overflow.
    177 		 *
    178 		 * N.B.: since x->fp_exp >= y->fp_exp, x->fp_sticky = 0.
    179 		 */
    180 		/* r->fp_mant = x->fp_mant - y->fp_mant */
    181 		FPU_SET_CARRY(y->fp_sticky);
    182 		FPU_SUBCS(r3, x->fp_mant[3], y->fp_mant[3]);
    183 		FPU_SUBCS(r2, x->fp_mant[2], y->fp_mant[2]);
    184 		FPU_SUBCS(r1, x->fp_mant[1], y->fp_mant[1]);
    185 		FPU_SUBC(r0, x->fp_mant[0], y->fp_mant[0]);
    186 		if (r0 < FP_2) {
    187 			/* cases i and ii */
    188 			if ((r0 | r1 | r2 | r3) == 0) {
    189 				/* case ii */
    190 				r->fp_class = FPC_ZERO;
    191 				r->fp_sign = rd == FSR_RD_RM;
    192 				return (r);
    193 			}
    194 		} else {
    195 			/*
    196 			 * Oops, case iii.  This can only occur when the
    197 			 * exponents were equal, in which case neither
    198 			 * x nor y have sticky bits set.  Flip the sign
    199 			 * (to y's sign) and negate the result to get y - x.
    200 			 */
    201 #ifdef DIAGNOSTIC
    202 			if (x->fp_exp != y->fp_exp || r->fp_sticky)
    203 				panic("fpu_add");
    204 #endif
    205 			r->fp_sign = y->fp_sign;
    206 			FPU_SUBS(r3, 0, r3);
    207 			FPU_SUBCS(r2, 0, r2);
    208 			FPU_SUBCS(r1, 0, r1);
    209 			FPU_SUBC(r0, 0, r0);
    210 		}
    211 		r->fp_mant[3] = r3;
    212 		r->fp_mant[2] = r2;
    213 		r->fp_mant[1] = r1;
    214 		r->fp_mant[0] = r0;
    215 		if (r0 < FP_1)
    216 			fpu_norm(r);
    217 	}
    218 	return (r);
    219 }
    220