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subr_time.c revision 1.2
      1  1.2     ad /*	$NetBSD: subr_time.c,v 1.2 2007/11/29 18:04:46 ad Exp $	*/
      2  1.1  pooka 
      3  1.1  pooka /*
      4  1.1  pooka  * Copyright (c) 1982, 1986, 1989, 1993
      5  1.1  pooka  *	The Regents of the University of California.  All rights reserved.
      6  1.1  pooka  *
      7  1.1  pooka  * Redistribution and use in source and binary forms, with or without
      8  1.1  pooka  * modification, are permitted provided that the following conditions
      9  1.1  pooka  * are met:
     10  1.1  pooka  * 1. Redistributions of source code must retain the above copyright
     11  1.1  pooka  *    notice, this list of conditions and the following disclaimer.
     12  1.1  pooka  * 2. Redistributions in binary form must reproduce the above copyright
     13  1.1  pooka  *    notice, this list of conditions and the following disclaimer in the
     14  1.1  pooka  *    documentation and/or other materials provided with the distribution.
     15  1.1  pooka  * 3. Neither the name of the University nor the names of its contributors
     16  1.1  pooka  *    may be used to endorse or promote products derived from this software
     17  1.1  pooka  *    without specific prior written permission.
     18  1.1  pooka  *
     19  1.1  pooka  * THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND
     20  1.1  pooka  * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
     21  1.1  pooka  * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
     22  1.1  pooka  * ARE DISCLAIMED.  IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
     23  1.1  pooka  * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
     24  1.1  pooka  * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
     25  1.1  pooka  * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
     26  1.1  pooka  * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
     27  1.1  pooka  * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
     28  1.1  pooka  * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
     29  1.1  pooka  * SUCH DAMAGE.
     30  1.1  pooka  *
     31  1.1  pooka  *	@(#)kern_clock.c	8.5 (Berkeley) 1/21/94
     32  1.1  pooka  *	@(#)kern_time.c 8.4 (Berkeley) 5/26/95
     33  1.1  pooka  */
     34  1.1  pooka 
     35  1.1  pooka #include <sys/cdefs.h>
     36  1.2     ad __KERNEL_RCSID(0, "$NetBSD: subr_time.c,v 1.2 2007/11/29 18:04:46 ad Exp $");
     37  1.1  pooka 
     38  1.1  pooka #include <sys/param.h>
     39  1.1  pooka #include <sys/kernel.h>
     40  1.1  pooka #include <sys/timex.h>
     41  1.1  pooka #include <sys/time.h>
     42  1.1  pooka #include <sys/timetc.h>
     43  1.2     ad #include <sys/intr.h>
     44  1.1  pooka 
     45  1.1  pooka #ifdef __HAVE_TIMECOUNTER
     46  1.1  pooka /*
     47  1.1  pooka  * Compute number of hz until specified time.  Used to compute second
     48  1.1  pooka  * argument to callout_reset() from an absolute time.
     49  1.1  pooka  */
     50  1.1  pooka int
     51  1.1  pooka hzto(struct timeval *tvp)
     52  1.1  pooka {
     53  1.1  pooka 	struct timeval now, tv;
     54  1.1  pooka 
     55  1.1  pooka 	tv = *tvp;	/* Don't modify original tvp. */
     56  1.1  pooka 	getmicrotime(&now);
     57  1.1  pooka 	timersub(&tv, &now, &tv);
     58  1.1  pooka 	return tvtohz(&tv);
     59  1.1  pooka }
     60  1.1  pooka #endif /* __HAVE_TIMECOUNTER */
     61  1.1  pooka 
     62  1.1  pooka /*
     63  1.1  pooka  * Compute number of ticks in the specified amount of time.
     64  1.1  pooka  */
     65  1.1  pooka int
     66  1.1  pooka tvtohz(struct timeval *tv)
     67  1.1  pooka {
     68  1.1  pooka 	unsigned long ticks;
     69  1.1  pooka 	long sec, usec;
     70  1.1  pooka 
     71  1.1  pooka 	/*
     72  1.1  pooka 	 * If the number of usecs in the whole seconds part of the time
     73  1.1  pooka 	 * difference fits in a long, then the total number of usecs will
     74  1.1  pooka 	 * fit in an unsigned long.  Compute the total and convert it to
     75  1.1  pooka 	 * ticks, rounding up and adding 1 to allow for the current tick
     76  1.1  pooka 	 * to expire.  Rounding also depends on unsigned long arithmetic
     77  1.1  pooka 	 * to avoid overflow.
     78  1.1  pooka 	 *
     79  1.1  pooka 	 * Otherwise, if the number of ticks in the whole seconds part of
     80  1.1  pooka 	 * the time difference fits in a long, then convert the parts to
     81  1.1  pooka 	 * ticks separately and add, using similar rounding methods and
     82  1.1  pooka 	 * overflow avoidance.  This method would work in the previous
     83  1.1  pooka 	 * case, but it is slightly slower and assumes that hz is integral.
     84  1.1  pooka 	 *
     85  1.1  pooka 	 * Otherwise, round the time difference down to the maximum
     86  1.1  pooka 	 * representable value.
     87  1.1  pooka 	 *
     88  1.1  pooka 	 * If ints are 32-bit, then the maximum value for any timeout in
     89  1.1  pooka 	 * 10ms ticks is 248 days.
     90  1.1  pooka 	 */
     91  1.1  pooka 	sec = tv->tv_sec;
     92  1.1  pooka 	usec = tv->tv_usec;
     93  1.1  pooka 
     94  1.1  pooka 	if (usec < 0) {
     95  1.1  pooka 		sec--;
     96  1.1  pooka 		usec += 1000000;
     97  1.1  pooka 	}
     98  1.1  pooka 
     99  1.1  pooka 	if (sec < 0 || (sec == 0 && usec <= 0)) {
    100  1.1  pooka 		/*
    101  1.1  pooka 		 * Would expire now or in the past.  Return 0 ticks.
    102  1.1  pooka 		 * This is different from the legacy hzto() interface,
    103  1.1  pooka 		 * and callers need to check for it.
    104  1.1  pooka 		 */
    105  1.1  pooka 		ticks = 0;
    106  1.1  pooka 	} else if (sec <= (LONG_MAX / 1000000))
    107  1.1  pooka 		ticks = (((sec * 1000000) + (unsigned long)usec + (tick - 1))
    108  1.1  pooka 		    / tick) + 1;
    109  1.1  pooka 	else if (sec <= (LONG_MAX / hz))
    110  1.1  pooka 		ticks = (sec * hz) +
    111  1.1  pooka 		    (((unsigned long)usec + (tick - 1)) / tick) + 1;
    112  1.1  pooka 	else
    113  1.1  pooka 		ticks = LONG_MAX;
    114  1.1  pooka 
    115  1.1  pooka 	if (ticks > INT_MAX)
    116  1.1  pooka 		ticks = INT_MAX;
    117  1.1  pooka 
    118  1.1  pooka 	return ((int)ticks);
    119  1.1  pooka }
    120  1.1  pooka 
    121  1.1  pooka #ifndef __HAVE_TIMECOUNTER
    122  1.1  pooka /*
    123  1.1  pooka  * Compute number of hz until specified time.  Used to compute second
    124  1.1  pooka  * argument to callout_reset() from an absolute time.
    125  1.1  pooka  */
    126  1.1  pooka int
    127  1.1  pooka hzto(struct timeval *tv)
    128  1.1  pooka {
    129  1.1  pooka 	unsigned long ticks;
    130  1.1  pooka 	long sec, usec;
    131  1.1  pooka 	int s;
    132  1.1  pooka 
    133  1.1  pooka 	/*
    134  1.1  pooka 	 * If the number of usecs in the whole seconds part of the time
    135  1.1  pooka 	 * difference fits in a long, then the total number of usecs will
    136  1.1  pooka 	 * fit in an unsigned long.  Compute the total and convert it to
    137  1.1  pooka 	 * ticks, rounding up and adding 1 to allow for the current tick
    138  1.1  pooka 	 * to expire.  Rounding also depends on unsigned long arithmetic
    139  1.1  pooka 	 * to avoid overflow.
    140  1.1  pooka 	 *
    141  1.1  pooka 	 * Otherwise, if the number of ticks in the whole seconds part of
    142  1.1  pooka 	 * the time difference fits in a long, then convert the parts to
    143  1.1  pooka 	 * ticks separately and add, using similar rounding methods and
    144  1.1  pooka 	 * overflow avoidance.  This method would work in the previous
    145  1.1  pooka 	 * case, but it is slightly slower and assume that hz is integral.
    146  1.1  pooka 	 *
    147  1.1  pooka 	 * Otherwise, round the time difference down to the maximum
    148  1.1  pooka 	 * representable value.
    149  1.1  pooka 	 *
    150  1.1  pooka 	 * If ints are 32-bit, then the maximum value for any timeout in
    151  1.1  pooka 	 * 10ms ticks is 248 days.
    152  1.1  pooka 	 */
    153  1.1  pooka 	s = splclock();
    154  1.1  pooka 	sec = tv->tv_sec - time.tv_sec;
    155  1.1  pooka 	usec = tv->tv_usec - time.tv_usec;
    156  1.1  pooka 	splx(s);
    157  1.1  pooka 
    158  1.1  pooka 	if (usec < 0) {
    159  1.1  pooka 		sec--;
    160  1.1  pooka 		usec += 1000000;
    161  1.1  pooka 	}
    162  1.1  pooka 
    163  1.1  pooka 	if (sec < 0 || (sec == 0 && usec <= 0)) {
    164  1.1  pooka 		/*
    165  1.1  pooka 		 * Would expire now or in the past.  Return 0 ticks.
    166  1.1  pooka 		 * This is different from the legacy hzto() interface,
    167  1.1  pooka 		 * and callers need to check for it.
    168  1.1  pooka 		 */
    169  1.1  pooka 		ticks = 0;
    170  1.1  pooka 	} else if (sec <= (LONG_MAX / 1000000))
    171  1.1  pooka 		ticks = (((sec * 1000000) + (unsigned long)usec + (tick - 1))
    172  1.1  pooka 		    / tick) + 1;
    173  1.1  pooka 	else if (sec <= (LONG_MAX / hz))
    174  1.1  pooka 		ticks = (sec * hz) +
    175  1.1  pooka 		    (((unsigned long)usec + (tick - 1)) / tick) + 1;
    176  1.1  pooka 	else
    177  1.1  pooka 		ticks = LONG_MAX;
    178  1.1  pooka 
    179  1.1  pooka 	if (ticks > INT_MAX)
    180  1.1  pooka 		ticks = INT_MAX;
    181  1.1  pooka 
    182  1.1  pooka 	return ((int)ticks);
    183  1.1  pooka }
    184  1.1  pooka #endif /* !__HAVE_TIMECOUNTER */
    185  1.1  pooka 
    186  1.1  pooka /*
    187  1.1  pooka  * Compute number of ticks in the specified amount of time.
    188  1.1  pooka  */
    189  1.1  pooka int
    190  1.1  pooka tstohz(struct timespec *ts)
    191  1.1  pooka {
    192  1.1  pooka 	struct timeval tv;
    193  1.1  pooka 
    194  1.1  pooka 	/*
    195  1.1  pooka 	 * usec has great enough resolution for hz, so convert to a
    196  1.1  pooka 	 * timeval and use tvtohz() above.
    197  1.1  pooka 	 */
    198  1.1  pooka 	TIMESPEC_TO_TIMEVAL(&tv, ts);
    199  1.1  pooka 	return tvtohz(&tv);
    200  1.1  pooka }
    201  1.1  pooka 
    202  1.1  pooka /*
    203  1.1  pooka  * Check that a proposed value to load into the .it_value or
    204  1.1  pooka  * .it_interval part of an interval timer is acceptable, and
    205  1.1  pooka  * fix it to have at least minimal value (i.e. if it is less
    206  1.1  pooka  * than the resolution of the clock, round it up.)
    207  1.1  pooka  */
    208  1.1  pooka int
    209  1.1  pooka itimerfix(struct timeval *tv)
    210  1.1  pooka {
    211  1.1  pooka 
    212  1.1  pooka 	if (tv->tv_sec < 0 || tv->tv_usec < 0 || tv->tv_usec >= 1000000)
    213  1.1  pooka 		return (EINVAL);
    214  1.1  pooka 	if (tv->tv_sec == 0 && tv->tv_usec != 0 && tv->tv_usec < tick)
    215  1.1  pooka 		tv->tv_usec = tick;
    216  1.1  pooka 	return (0);
    217  1.1  pooka }
    218  1.1  pooka 
    219  1.1  pooka int
    220  1.1  pooka itimespecfix(struct timespec *ts)
    221  1.1  pooka {
    222  1.1  pooka 
    223  1.1  pooka 	if (ts->tv_sec < 0 || ts->tv_nsec < 0 || ts->tv_nsec >= 1000000000)
    224  1.1  pooka 		return (EINVAL);
    225  1.1  pooka 	if (ts->tv_sec == 0 && ts->tv_nsec != 0 && ts->tv_nsec < tick * 1000)
    226  1.1  pooka 		ts->tv_nsec = tick * 1000;
    227  1.1  pooka 	return (0);
    228  1.1  pooka }
    229