subr_time.c revision 1.2 1 /* $NetBSD: subr_time.c,v 1.2 2007/11/29 18:04:46 ad Exp $ */
2
3 /*
4 * Copyright (c) 1982, 1986, 1989, 1993
5 * The Regents of the University of California. All rights reserved.
6 *
7 * Redistribution and use in source and binary forms, with or without
8 * modification, are permitted provided that the following conditions
9 * are met:
10 * 1. Redistributions of source code must retain the above copyright
11 * notice, this list of conditions and the following disclaimer.
12 * 2. Redistributions in binary form must reproduce the above copyright
13 * notice, this list of conditions and the following disclaimer in the
14 * documentation and/or other materials provided with the distribution.
15 * 3. Neither the name of the University nor the names of its contributors
16 * may be used to endorse or promote products derived from this software
17 * without specific prior written permission.
18 *
19 * THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND
20 * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
21 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
22 * ARE DISCLAIMED. IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
23 * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
24 * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
25 * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
26 * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
27 * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
28 * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
29 * SUCH DAMAGE.
30 *
31 * @(#)kern_clock.c 8.5 (Berkeley) 1/21/94
32 * @(#)kern_time.c 8.4 (Berkeley) 5/26/95
33 */
34
35 #include <sys/cdefs.h>
36 __KERNEL_RCSID(0, "$NetBSD: subr_time.c,v 1.2 2007/11/29 18:04:46 ad Exp $");
37
38 #include <sys/param.h>
39 #include <sys/kernel.h>
40 #include <sys/timex.h>
41 #include <sys/time.h>
42 #include <sys/timetc.h>
43 #include <sys/intr.h>
44
45 #ifdef __HAVE_TIMECOUNTER
46 /*
47 * Compute number of hz until specified time. Used to compute second
48 * argument to callout_reset() from an absolute time.
49 */
50 int
51 hzto(struct timeval *tvp)
52 {
53 struct timeval now, tv;
54
55 tv = *tvp; /* Don't modify original tvp. */
56 getmicrotime(&now);
57 timersub(&tv, &now, &tv);
58 return tvtohz(&tv);
59 }
60 #endif /* __HAVE_TIMECOUNTER */
61
62 /*
63 * Compute number of ticks in the specified amount of time.
64 */
65 int
66 tvtohz(struct timeval *tv)
67 {
68 unsigned long ticks;
69 long sec, usec;
70
71 /*
72 * If the number of usecs in the whole seconds part of the time
73 * difference fits in a long, then the total number of usecs will
74 * fit in an unsigned long. Compute the total and convert it to
75 * ticks, rounding up and adding 1 to allow for the current tick
76 * to expire. Rounding also depends on unsigned long arithmetic
77 * to avoid overflow.
78 *
79 * Otherwise, if the number of ticks in the whole seconds part of
80 * the time difference fits in a long, then convert the parts to
81 * ticks separately and add, using similar rounding methods and
82 * overflow avoidance. This method would work in the previous
83 * case, but it is slightly slower and assumes that hz is integral.
84 *
85 * Otherwise, round the time difference down to the maximum
86 * representable value.
87 *
88 * If ints are 32-bit, then the maximum value for any timeout in
89 * 10ms ticks is 248 days.
90 */
91 sec = tv->tv_sec;
92 usec = tv->tv_usec;
93
94 if (usec < 0) {
95 sec--;
96 usec += 1000000;
97 }
98
99 if (sec < 0 || (sec == 0 && usec <= 0)) {
100 /*
101 * Would expire now or in the past. Return 0 ticks.
102 * This is different from the legacy hzto() interface,
103 * and callers need to check for it.
104 */
105 ticks = 0;
106 } else if (sec <= (LONG_MAX / 1000000))
107 ticks = (((sec * 1000000) + (unsigned long)usec + (tick - 1))
108 / tick) + 1;
109 else if (sec <= (LONG_MAX / hz))
110 ticks = (sec * hz) +
111 (((unsigned long)usec + (tick - 1)) / tick) + 1;
112 else
113 ticks = LONG_MAX;
114
115 if (ticks > INT_MAX)
116 ticks = INT_MAX;
117
118 return ((int)ticks);
119 }
120
121 #ifndef __HAVE_TIMECOUNTER
122 /*
123 * Compute number of hz until specified time. Used to compute second
124 * argument to callout_reset() from an absolute time.
125 */
126 int
127 hzto(struct timeval *tv)
128 {
129 unsigned long ticks;
130 long sec, usec;
131 int s;
132
133 /*
134 * If the number of usecs in the whole seconds part of the time
135 * difference fits in a long, then the total number of usecs will
136 * fit in an unsigned long. Compute the total and convert it to
137 * ticks, rounding up and adding 1 to allow for the current tick
138 * to expire. Rounding also depends on unsigned long arithmetic
139 * to avoid overflow.
140 *
141 * Otherwise, if the number of ticks in the whole seconds part of
142 * the time difference fits in a long, then convert the parts to
143 * ticks separately and add, using similar rounding methods and
144 * overflow avoidance. This method would work in the previous
145 * case, but it is slightly slower and assume that hz is integral.
146 *
147 * Otherwise, round the time difference down to the maximum
148 * representable value.
149 *
150 * If ints are 32-bit, then the maximum value for any timeout in
151 * 10ms ticks is 248 days.
152 */
153 s = splclock();
154 sec = tv->tv_sec - time.tv_sec;
155 usec = tv->tv_usec - time.tv_usec;
156 splx(s);
157
158 if (usec < 0) {
159 sec--;
160 usec += 1000000;
161 }
162
163 if (sec < 0 || (sec == 0 && usec <= 0)) {
164 /*
165 * Would expire now or in the past. Return 0 ticks.
166 * This is different from the legacy hzto() interface,
167 * and callers need to check for it.
168 */
169 ticks = 0;
170 } else if (sec <= (LONG_MAX / 1000000))
171 ticks = (((sec * 1000000) + (unsigned long)usec + (tick - 1))
172 / tick) + 1;
173 else if (sec <= (LONG_MAX / hz))
174 ticks = (sec * hz) +
175 (((unsigned long)usec + (tick - 1)) / tick) + 1;
176 else
177 ticks = LONG_MAX;
178
179 if (ticks > INT_MAX)
180 ticks = INT_MAX;
181
182 return ((int)ticks);
183 }
184 #endif /* !__HAVE_TIMECOUNTER */
185
186 /*
187 * Compute number of ticks in the specified amount of time.
188 */
189 int
190 tstohz(struct timespec *ts)
191 {
192 struct timeval tv;
193
194 /*
195 * usec has great enough resolution for hz, so convert to a
196 * timeval and use tvtohz() above.
197 */
198 TIMESPEC_TO_TIMEVAL(&tv, ts);
199 return tvtohz(&tv);
200 }
201
202 /*
203 * Check that a proposed value to load into the .it_value or
204 * .it_interval part of an interval timer is acceptable, and
205 * fix it to have at least minimal value (i.e. if it is less
206 * than the resolution of the clock, round it up.)
207 */
208 int
209 itimerfix(struct timeval *tv)
210 {
211
212 if (tv->tv_sec < 0 || tv->tv_usec < 0 || tv->tv_usec >= 1000000)
213 return (EINVAL);
214 if (tv->tv_sec == 0 && tv->tv_usec != 0 && tv->tv_usec < tick)
215 tv->tv_usec = tick;
216 return (0);
217 }
218
219 int
220 itimespecfix(struct timespec *ts)
221 {
222
223 if (ts->tv_sec < 0 || ts->tv_nsec < 0 || ts->tv_nsec >= 1000000000)
224 return (EINVAL);
225 if (ts->tv_sec == 0 && ts->tv_nsec != 0 && ts->tv_nsec < tick * 1000)
226 ts->tv_nsec = tick * 1000;
227 return (0);
228 }
229