1 1.1 cgd The cal(1) date routines were written from scratch, basically from first 2 1.1 cgd principles. The algorithm for calculating the day of week from any 3 1.1 cgd Gregorian date was "reverse engineered". This was necessary as most of 4 1.1 cgd the documented algorithms have to do with date calculations for other 5 1.1 cgd calendars (e.g. julian) and are only accurate when converted to gregorian 6 1.1 cgd within a narrow range of dates. 7 1.1 cgd 8 1.1 cgd 1 Jan 1 is a Saturday because that's what cal says and I couldn't change 9 1.1 cgd that even if I was dumb enough to try. From this we can easily calculate 10 1.1 cgd the day of week for any date. The algorithm for a zero based day of week: 11 1.1 cgd 12 1.1 cgd calculate the number of days in all prior years (year-1)*365 13 1.1 cgd add the number of leap years (days?) since year 1 14 1.1 cgd (not including this year as that is covered later) 15 1.1 cgd add the day number within the year 16 1.1 cgd this compensates for the non-inclusive leap year 17 1.1 cgd calculation 18 1.1 cgd if the day in question occurs before the gregorian reformation 19 1.1 cgd (3 sep 1752 for our purposes), then simply return 20 1.1 cgd (value so far - 1 + SATURDAY's value of 6) modulo 7. 21 1.1 cgd if the day in question occurs during the reformation (3 sep 1752 22 1.1 cgd to 13 sep 1752 inclusive) return THURSDAY. This is my 23 1.1 cgd idea of what happened then. It does not matter much as 24 1.1 cgd this program never tries to find day of week for any day 25 1.1 cgd that is not the first of a month. 26 1.1 cgd otherwise, after the reformation, use the same formula as the 27 1.1 cgd days before with the additional step of subtracting the 28 1.1 cgd number of days (11) that were adjusted out of the calendar 29 1.1 cgd just before taking the modulo. 30 1.1 cgd 31 1.1 cgd It must be noted that the number of leap years calculation is sensitive 32 1.1 cgd to the date for which the leap year is being calculated. A year that occurs 33 1.1 cgd before the reformation is determined to be a leap year if its modulo of 34 1.1 cgd 4 equals zero. But after the reformation, a year is only a leap year if 35 1.1 cgd its modulo of 4 equals zero and its modulo of 100 does not. Of course, 36 1.1 cgd there is an exception for these century years. If the modulo of 400 equals 37 1.1 cgd zero, then the year is a leap year anyway. This is, in fact, what the 38 1.1 cgd gregorian reformation was all about (a bit of error in the old algorithm 39 1.1 cgd that caused the calendar to be inaccurate.) 40 1.1 cgd 41 1.1 cgd Once we have the day in year for the first of the month in question, the 42 1.1 cgd rest is trivial. 43