str.c revision 1.84.2.1 1 /* $NetBSD: str.c,v 1.84.2.1 2021/05/31 22:15:25 cjep Exp $ */
2
3 /*
4 * Copyright (c) 1988, 1989, 1990, 1993
5 * The Regents of the University of California. All rights reserved.
6 *
7 * This code is derived from software contributed to Berkeley by
8 * Adam de Boor.
9 *
10 * Redistribution and use in source and binary forms, with or without
11 * modification, are permitted provided that the following conditions
12 * are met:
13 * 1. Redistributions of source code must retain the above copyright
14 * notice, this list of conditions and the following disclaimer.
15 * 2. Redistributions in binary form must reproduce the above copyright
16 * notice, this list of conditions and the following disclaimer in the
17 * documentation and/or other materials provided with the distribution.
18 * 3. Neither the name of the University nor the names of its contributors
19 * may be used to endorse or promote products derived from this software
20 * without specific prior written permission.
21 *
22 * THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND
23 * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
24 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
25 * ARE DISCLAIMED. IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
26 * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
27 * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
28 * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
29 * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
30 * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
31 * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
32 * SUCH DAMAGE.
33 */
34
35 /*
36 * Copyright (c) 1989 by Berkeley Softworks
37 * All rights reserved.
38 *
39 * This code is derived from software contributed to Berkeley by
40 * Adam de Boor.
41 *
42 * Redistribution and use in source and binary forms, with or without
43 * modification, are permitted provided that the following conditions
44 * are met:
45 * 1. Redistributions of source code must retain the above copyright
46 * notice, this list of conditions and the following disclaimer.
47 * 2. Redistributions in binary form must reproduce the above copyright
48 * notice, this list of conditions and the following disclaimer in the
49 * documentation and/or other materials provided with the distribution.
50 * 3. All advertising materials mentioning features or use of this software
51 * must display the following acknowledgement:
52 * This product includes software developed by the University of
53 * California, Berkeley and its contributors.
54 * 4. Neither the name of the University nor the names of its contributors
55 * may be used to endorse or promote products derived from this software
56 * without specific prior written permission.
57 *
58 * THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND
59 * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
60 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
61 * ARE DISCLAIMED. IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
62 * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
63 * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
64 * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
65 * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
66 * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
67 * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
68 * SUCH DAMAGE.
69 */
70
71 #include "make.h"
72
73 /* "@(#)str.c 5.8 (Berkeley) 6/1/90" */
74 MAKE_RCSID("$NetBSD: str.c,v 1.84.2.1 2021/05/31 22:15:25 cjep Exp $");
75
76 /* Return the concatenation of s1 and s2, freshly allocated. */
77 char *
78 str_concat2(const char *s1, const char *s2)
79 {
80 size_t len1 = strlen(s1);
81 size_t len2 = strlen(s2);
82 char *result = bmake_malloc(len1 + len2 + 1);
83 memcpy(result, s1, len1);
84 memcpy(result + len1, s2, len2 + 1);
85 return result;
86 }
87
88 /* Return the concatenation of s1, s2 and s3, freshly allocated. */
89 char *
90 str_concat3(const char *s1, const char *s2, const char *s3)
91 {
92 size_t len1 = strlen(s1);
93 size_t len2 = strlen(s2);
94 size_t len3 = strlen(s3);
95 char *result = bmake_malloc(len1 + len2 + len3 + 1);
96 memcpy(result, s1, len1);
97 memcpy(result + len1, s2, len2);
98 memcpy(result + len1 + len2, s3, len3 + 1);
99 return result;
100 }
101
102 /*
103 * Fracture a string into an array of words (as delineated by tabs or spaces)
104 * taking quotation marks into account.
105 *
106 * If expand is true, quotes are removed and escape sequences such as \r, \t,
107 * etc... are expanded. In this case, return NULL on parse errors.
108 *
109 * Returns the fractured words, which must be freed later using Words_Free,
110 * unless the returned Words.words was NULL.
111 */
112 SubstringWords
113 Substring_Words(const char *str, bool expand)
114 {
115 size_t str_len;
116 char *words_buf;
117 size_t words_cap;
118 Substring *words;
119 size_t words_len;
120 char inquote;
121 char *word_start;
122 char *word_end;
123 const char *str_p;
124
125 /* XXX: why only hspace, not whitespace? */
126 cpp_skip_hspace(&str); /* skip leading space chars. */
127
128 /* words_buf holds the words, separated by '\0'. */
129 str_len = strlen(str);
130 words_buf = bmake_malloc(str_len + 1);
131
132 words_cap = str_len / 5 > 50 ? str_len / 5 : 50;
133 words = bmake_malloc((words_cap + 1) * sizeof(words[0]));
134
135 /*
136 * copy the string; at the same time, parse backslashes,
137 * quotes and build the word list.
138 */
139 words_len = 0;
140 inquote = '\0';
141 word_start = words_buf;
142 word_end = words_buf;
143 for (str_p = str;; str_p++) {
144 char ch = *str_p;
145 switch (ch) {
146 case '"':
147 case '\'':
148 if (inquote != '\0') {
149 if (inquote == ch)
150 inquote = '\0';
151 else
152 break;
153 } else {
154 inquote = ch;
155 /* Don't miss "" or '' */
156 if (word_start == NULL && str_p[1] == inquote) {
157 if (!expand) {
158 word_start = word_end;
159 *word_end++ = ch;
160 } else
161 word_start = word_end + 1;
162 str_p++;
163 inquote = '\0';
164 break;
165 }
166 }
167 if (!expand) {
168 if (word_start == NULL)
169 word_start = word_end;
170 *word_end++ = ch;
171 }
172 continue;
173 case ' ':
174 case '\t':
175 case '\n':
176 if (inquote != '\0')
177 break;
178 if (word_start == NULL)
179 continue;
180 /* FALLTHROUGH */
181 case '\0':
182 /*
183 * end of a token -- make sure there's enough words
184 * space and save off a pointer.
185 */
186 if (word_start == NULL)
187 goto done;
188
189 *word_end++ = '\0';
190 if (words_len == words_cap) {
191 size_t new_size;
192 words_cap *= 2;
193 new_size = (words_cap + 1) * sizeof(words[0]);
194 words = bmake_realloc(words, new_size);
195 }
196 words[words_len++] =
197 Substring_Init(word_start, word_end - 1);
198 word_start = NULL;
199 if (ch == '\n' || ch == '\0') {
200 if (expand && inquote != '\0') {
201 SubstringWords res;
202
203 free(words);
204 free(words_buf);
205
206 res.words = NULL;
207 res.len = 0;
208 res.freeIt = NULL;
209 return res;
210 }
211 goto done;
212 }
213 continue;
214 case '\\':
215 if (!expand) {
216 if (word_start == NULL)
217 word_start = word_end;
218 *word_end++ = '\\';
219 /* catch '\' at end of line */
220 if (str_p[1] == '\0')
221 continue;
222 ch = *++str_p;
223 break;
224 }
225
226 switch (ch = *++str_p) {
227 case '\0':
228 case '\n':
229 /* hmmm; fix it up as best we can */
230 ch = '\\';
231 str_p--;
232 break;
233 case 'b':
234 ch = '\b';
235 break;
236 case 'f':
237 ch = '\f';
238 break;
239 case 'n':
240 ch = '\n';
241 break;
242 case 'r':
243 ch = '\r';
244 break;
245 case 't':
246 ch = '\t';
247 break;
248 }
249 break;
250 }
251 if (word_start == NULL)
252 word_start = word_end;
253 *word_end++ = ch;
254 }
255 done:
256 words[words_len] = Substring_Init(NULL, NULL); /* useful for argv */
257
258 {
259 SubstringWords result;
260
261 result.words = words;
262 result.len = words_len;
263 result.freeIt = words_buf;
264 return result;
265 }
266 }
267
268 Words
269 Str_Words(const char *str, bool expand)
270 {
271 SubstringWords swords;
272 Words words;
273 size_t i;
274
275 swords = Substring_Words(str, expand);
276 if (swords.words == NULL) {
277 words.words = NULL;
278 words.len = 0;
279 words.freeIt = NULL;
280 return words;
281 }
282
283 words.words = bmake_malloc((swords.len + 1) * sizeof(words.words[0]));
284 words.len = swords.len;
285 words.freeIt = swords.freeIt;
286 for (i = 0; i < swords.len + 1; i++)
287 words.words[i] = UNCONST(swords.words[i].start);
288 free(swords.words);
289 return words;
290 }
291
292 /*
293 * Str_Match -- Test if a string matches a pattern like "*.[ch]".
294 * The following special characters are known *?\[] (as in fnmatch(3)).
295 *
296 * XXX: this function does not detect or report malformed patterns.
297 */
298 bool
299 Str_Match(const char *str, const char *pat)
300 {
301 for (;;) {
302 /*
303 * See if we're at the end of both the pattern and the
304 * string. If so, we succeeded. If we're at the end of the
305 * pattern but not at the end of the string, we failed.
306 */
307 if (*pat == '\0')
308 return *str == '\0';
309 if (*str == '\0' && *pat != '*')
310 return false;
311
312 /*
313 * A '*' in the pattern matches any substring. We handle this
314 * by calling ourselves for each suffix of the string.
315 */
316 if (*pat == '*') {
317 pat++;
318 while (*pat == '*')
319 pat++;
320 if (*pat == '\0')
321 return true;
322 while (*str != '\0') {
323 if (Str_Match(str, pat))
324 return true;
325 str++;
326 }
327 return false;
328 }
329
330 /* A '?' in the pattern matches any single character. */
331 if (*pat == '?')
332 goto thisCharOK;
333
334 /*
335 * A '[' in the pattern matches a character from a list.
336 * The '[' is followed by the list of acceptable characters,
337 * or by ranges (two characters separated by '-'). In these
338 * character lists, the backslash is an ordinary character.
339 */
340 if (*pat == '[') {
341 bool neg = pat[1] == '^';
342 pat += neg ? 2 : 1;
343
344 for (;;) {
345 if (*pat == ']' || *pat == '\0') {
346 if (neg)
347 break;
348 return false;
349 }
350 /*
351 * XXX: This naive comparison makes the
352 * control flow of the pattern parser
353 * dependent on the actual value of the
354 * string. This is unpredictable. It may be
355 * though that the code only looks wrong but
356 * actually all code paths result in the same
357 * behavior. This needs further tests.
358 */
359 if (*pat == *str)
360 break;
361 if (pat[1] == '-') {
362 if (pat[2] == '\0')
363 return neg;
364 if (*pat <= *str && pat[2] >= *str)
365 break;
366 if (*pat >= *str && pat[2] <= *str)
367 break;
368 pat += 2;
369 }
370 pat++;
371 }
372 if (neg && *pat != ']' && *pat != '\0')
373 return false;
374 while (*pat != ']' && *pat != '\0')
375 pat++;
376 if (*pat == '\0')
377 pat--;
378 goto thisCharOK;
379 }
380
381 /*
382 * A backslash in the pattern matches the character following
383 * it exactly.
384 */
385 if (*pat == '\\') {
386 pat++;
387 if (*pat == '\0')
388 return false;
389 }
390
391 if (*pat != *str)
392 return false;
393
394 thisCharOK:
395 pat++;
396 str++;
397 }
398 }
399