hash.c revision 1.1 1 /* $OpenBSD: hash.c,v 1.1 1997/04/15 22:06:11 maja Exp $ */
2 /*
3 * Copyright (c) 1995
4 * Bill Paul <wpaul (at) ctr.columbia.edu>. All rights reserved.
5 *
6 * Redistribution and use in source and binary forms, with or without
7 * modification, are permitted provided that the following conditions
8 * are met:
9 * 1. Redistributions of source code must retain the above copyright
10 * notice, this list of conditions and the following disclaimer.
11 * 2. Redistributions in binary form must reproduce the above copyright
12 * notice, this list of conditions and the following disclaimer in the
13 * documentation and/or other materials provided with the distribution.
14 * 3. All advertising materials mentioning features or use of this software
15 * must display the following acknowledgement:
16 * This product includes software developed by Bill Paul.
17 * 4. Neither the name of the author nor the names of any co-contributors
18 * may be used to endorse or promote products derived from this software
19 * without specific prior written permission.
20 *
21 * THIS SOFTWARE IS PROVIDED BY Bill Paul AND CONTRIBUTORS ``AS IS'' AND
22 * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
23 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
24 * ARE DISCLAIMED. IN NO EVENT SHALL Bill Paul OR CONTRIBUTORS BE LIABLE
25 * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
26 * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
27 * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
28 * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
29 * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
30 * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
31 * SUCH DAMAGE.
32 *
33 * $FreeBSD: hash.c,v 1.4 1997/02/22 14:22:01 peter Exp $
34 */
35
36 #include <stdio.h>
37 #include <stdlib.h>
38 #include <string.h>
39 #include <sys/types.h>
40 #include "hash.h"
41
42 #ifndef lint
43 static const char rcsid[] = "$OpenBSD: hash.c,v 1.1 1997/04/15 22:06:11 maja Exp $";
44 #endif
45
46 /*
47 * This hash function is stolen directly from the
48 * Berkeley DB package. It already exists inside libc, but
49 * it's declared static which prevents us from calling it
50 * from here.
51 */
52 /*
53 * OZ's original sdbm hash
54 */
55 u_int32_t
56 hash(keyarg, len)
57 const void *keyarg;
58 register size_t len;
59 {
60 register const u_char *key;
61 register size_t loop;
62 register u_int32_t h;
63
64 #define HASHC h = *key++ + 65599 * h
65
66 h = 0;
67 key = keyarg;
68 if (len > 0) {
69 loop = (len + 8 - 1) >> 3;
70
71 switch (len & (8 - 1)) {
72 case 0:
73 do {
74 HASHC;
75 /* FALLTHROUGH */
76 case 7:
77 HASHC;
78 /* FALLTHROUGH */
79 case 6:
80 HASHC;
81 /* FALLTHROUGH */
82 case 5:
83 HASHC;
84 /* FALLTHROUGH */
85 case 4:
86 HASHC;
87 /* FALLTHROUGH */
88 case 3:
89 HASHC;
90 /* FALLTHROUGH */
91 case 2:
92 HASHC;
93 /* FALLTHROUGH */
94 case 1:
95 HASHC;
96 } while (--loop);
97 }
98 }
99 return (h);
100 }
101
102 /*
103 * Generate a hash value for a given key (character string).
104 * We mask off all but the lower 8 bits since our table array
105 * can only hold 256 elements.
106 */
107 u_int32_t hashkey(key)
108 char *key;
109 {
110
111 if (key == NULL)
112 return (-1);
113 return(hash((void *)key, strlen(key)) & HASH_MASK);
114 }
115
116 /* Find an entry in the hash table (may be hanging off a linked list). */
117 char *lookup(table, key)
118 struct group_entry *table[];
119 char *key;
120 {
121 struct group_entry *cur;
122
123 cur = table[hashkey(key)];
124
125 while (cur) {
126 if (!strcmp(cur->key, key))
127 return(cur->data);
128 cur = cur->next;
129 }
130
131 return(NULL);
132 }
133
134 /*
135 * Store an entry in the main netgroup hash table. Here's how this
136 * works: the table can only be so big when we initialize it (TABLESIZE)
137 * but the number of netgroups in the /etc/netgroup file could easily be
138 * much larger than the table. Since our hash values are adjusted to
139 * never be greater than TABLESIZE too, this means it won't be long before
140 * we find ourselves with two keys that hash to the same value.
141 *
142 * One way to deal with this is to malloc(2) a second table and start
143 * doing indirection, but this is a pain in the butt and it's not worth
144 * going to all that trouble for a dinky little program like this. Instead,
145 * we turn each table entry into a linked list and simply link keys
146 * with the same hash value together at the same index location within
147 * the table.
148 *
149 * That's a lot of comment for such a small piece of code, isn't it.
150 */
151 void store (table, key, data)
152 struct group_entry *table[];
153 char *key, *data;
154 {
155 struct group_entry *new;
156 u_int32_t i;
157
158 i = hashkey(key);
159
160 new = (struct group_entry *)malloc(sizeof(struct group_entry));
161 new->key = strdup(key);
162 new->data = strdup(data);
163 new->next = table[i];
164 table[i] = new;
165
166 return;
167 }
168
169 /*
170 * Store a group member entry and/or update its grouplist. This is
171 * a bit more complicated than the previous function since we have to
172 * maintain not only the hash table of group members, each group member
173 * structure also has a linked list of groups hung off it. If handed
174 * a member name that we haven't encountered before, we have to do
175 * two things: add that member to the table (possibly hanging them
176 * off the end of a linked list, as above), and add a group name to
177 * the member's grouplist list. If we're handed a name that already has
178 * an entry in the table, then we just have to do one thing, which is
179 * to update its grouplist.
180 */
181 void mstore (table, key, data, domain)
182 struct member_entry *table[];
183 char *key, *data, *domain;
184 {
185 struct member_entry *cur, *new;
186 struct grouplist *tmp,*p;
187 u_int32_t i;
188
189 i = hashkey(key);
190 cur = table[i];
191
192 tmp = (struct grouplist *)malloc(sizeof(struct grouplist));
193 tmp->groupname = strdup(data);
194 tmp->next = NULL;
195
196 /* Check if all we have to do is insert a new groupname. */
197 while (cur) {
198 if (!strcmp(cur->key, key) && !strcmp(cur->domain,domain)) {
199 p = cur->groups;
200 while(p) {
201 if (!strcmp(p->groupname,data))
202 return;
203 p = p->next;
204 }
205 tmp->next = cur->groups;
206 cur->groups = tmp;
207 return;
208 }
209 cur = cur->next;
210 }
211
212 /* Didn't find a match -- add the whole mess to the table. */
213 new = (struct member_entry *)malloc(sizeof(struct member_entry));
214 new->key = strdup(key);
215 new->domain = strdup(domain);
216 new->groups = tmp;
217 new->next = table[i];
218 table[i] = new;
219
220 return;
221 }
222