ir3_group.c revision b8e80941
1/* 2 * Copyright (C) 2014 Rob Clark <robclark@freedesktop.org> 3 * 4 * Permission is hereby granted, free of charge, to any person obtaining a 5 * copy of this software and associated documentation files (the "Software"), 6 * to deal in the Software without restriction, including without limitation 7 * the rights to use, copy, modify, merge, publish, distribute, sublicense, 8 * and/or sell copies of the Software, and to permit persons to whom the 9 * Software is furnished to do so, subject to the following conditions: 10 * 11 * The above copyright notice and this permission notice (including the next 12 * paragraph) shall be included in all copies or substantial portions of the 13 * Software. 14 * 15 * THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR 16 * IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY, 17 * FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL 18 * THE AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER 19 * LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, 20 * OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE 21 * SOFTWARE. 22 * 23 * Authors: 24 * Rob Clark <robclark@freedesktop.org> 25 */ 26 27#include "ir3.h" 28 29/* 30 * Find/group instruction neighbors: 31 */ 32 33/* bleh.. we need to do the same group_n() thing for both inputs/outputs 34 * (where we have a simple instr[] array), and fanin nodes (where we have 35 * an extra indirection via reg->instr). 36 */ 37struct group_ops { 38 struct ir3_instruction *(*get)(void *arr, int idx); 39 void (*insert_mov)(void *arr, int idx, struct ir3_instruction *instr); 40}; 41 42static struct ir3_instruction *arr_get(void *arr, int idx) 43{ 44 return ((struct ir3_instruction **)arr)[idx]; 45} 46static void arr_insert_mov_out(void *arr, int idx, struct ir3_instruction *instr) 47{ 48 ((struct ir3_instruction **)arr)[idx] = 49 ir3_MOV(instr->block, instr, TYPE_F32); 50} 51static void arr_insert_mov_in(void *arr, int idx, struct ir3_instruction *instr) 52{ 53 /* so, we can't insert a mov in front of a meta:in.. and the downstream 54 * instruction already has a pointer to 'instr'. So we cheat a bit and 55 * morph the meta:in instruction into a mov and insert a new meta:in 56 * in front. 57 */ 58 struct ir3_instruction *in; 59 60 debug_assert(instr->regs_count == 1); 61 62 in = ir3_instr_create(instr->block, OPC_META_INPUT); 63 in->inout.block = instr->block; 64 ir3_reg_create(in, instr->regs[0]->num, 0); 65 66 /* create src reg for meta:in and fixup to now be a mov: */ 67 ir3_reg_create(instr, 0, IR3_REG_SSA)->instr = in; 68 instr->opc = OPC_MOV; 69 instr->cat1.src_type = TYPE_F32; 70 instr->cat1.dst_type = TYPE_F32; 71 72 ((struct ir3_instruction **)arr)[idx] = in; 73} 74static struct group_ops arr_ops_out = { arr_get, arr_insert_mov_out }; 75static struct group_ops arr_ops_in = { arr_get, arr_insert_mov_in }; 76 77static struct ir3_instruction *instr_get(void *arr, int idx) 78{ 79 return ssa(((struct ir3_instruction *)arr)->regs[idx+1]); 80} 81static void 82instr_insert_mov(void *arr, int idx, struct ir3_instruction *instr) 83{ 84 ((struct ir3_instruction *)arr)->regs[idx+1]->instr = 85 ir3_MOV(instr->block, instr, TYPE_F32); 86} 87static struct group_ops instr_ops = { instr_get, instr_insert_mov }; 88 89/* verify that cur != instr, but cur is also not in instr's neighbor-list: */ 90static bool 91in_neighbor_list(struct ir3_instruction *instr, struct ir3_instruction *cur, int pos) 92{ 93 int idx = 0; 94 95 if (!instr) 96 return false; 97 98 if (instr == cur) 99 return true; 100 101 for (instr = ir3_neighbor_first(instr); instr; instr = instr->cp.right) 102 if ((idx++ != pos) && (instr == cur)) 103 return true; 104 105 return false; 106} 107 108static void 109group_n(struct group_ops *ops, void *arr, unsigned n) 110{ 111 unsigned i, j; 112 113 /* first pass, figure out what has conflicts and needs a mov 114 * inserted. Do this up front, before starting to setup 115 * left/right neighbor pointers. Trying to do it in a single 116 * pass could result in a situation where we can't even setup 117 * the mov's right neighbor ptr if the next instr also needs 118 * a mov. 119 */ 120restart: 121 for (i = 0; i < n; i++) { 122 struct ir3_instruction *instr = ops->get(arr, i); 123 if (instr) { 124 struct ir3_instruction *left = (i > 0) ? ops->get(arr, i - 1) : NULL; 125 struct ir3_instruction *right = (i < (n-1)) ? ops->get(arr, i + 1) : NULL; 126 bool conflict; 127 128 /* check for left/right neighbor conflicts: */ 129 conflict = conflicts(instr->cp.left, left) || 130 conflicts(instr->cp.right, right); 131 132 /* Mixing array elements and higher register classes 133 * (ie. groups) doesn't really work out in RA. See: 134 * 135 * https://trello.com/c/DqeDkeVf/156-bug-with-stk-70frag 136 */ 137 if (instr->regs[0]->flags & IR3_REG_ARRAY) 138 conflict = true; 139 140 /* we also can't have an instr twice in the group: */ 141 for (j = i + 1; (j < n) && !conflict; j++) 142 if (in_neighbor_list(ops->get(arr, j), instr, i)) 143 conflict = true; 144 145 if (conflict) { 146 ops->insert_mov(arr, i, instr); 147 /* inserting the mov may have caused a conflict 148 * against the previous: 149 */ 150 goto restart; 151 } 152 } 153 } 154 155 /* second pass, now that we've inserted mov's, fixup left/right 156 * neighbors. This is guaranteed to succeed, since by definition 157 * the newly inserted mov's cannot conflict with anything. 158 */ 159 for (i = 0; i < n; i++) { 160 struct ir3_instruction *instr = ops->get(arr, i); 161 if (instr) { 162 struct ir3_instruction *left = (i > 0) ? ops->get(arr, i - 1) : NULL; 163 struct ir3_instruction *right = (i < (n-1)) ? ops->get(arr, i + 1) : NULL; 164 165 debug_assert(!conflicts(instr->cp.left, left)); 166 if (left) { 167 instr->cp.left_cnt++; 168 instr->cp.left = left; 169 } 170 171 debug_assert(!conflicts(instr->cp.right, right)); 172 if (right) { 173 instr->cp.right_cnt++; 174 instr->cp.right = right; 175 } 176 } 177 } 178} 179 180static void 181instr_find_neighbors(struct ir3_instruction *instr) 182{ 183 struct ir3_instruction *src; 184 185 if (ir3_instr_check_mark(instr)) 186 return; 187 188 if (instr->opc == OPC_META_FI) 189 group_n(&instr_ops, instr, instr->regs_count - 1); 190 191 foreach_ssa_src(src, instr) 192 instr_find_neighbors(src); 193} 194 195/* a bit of sadness.. we can't have "holes" in inputs from PoV of 196 * register assignment, they still need to be grouped together. So 197 * we need to insert dummy/padding instruction for grouping, and 198 * then take it back out again before anyone notices. 199 */ 200static void 201pad_and_group_input(struct ir3_instruction **input, unsigned n) 202{ 203 int i, mask = 0; 204 struct ir3_block *block = NULL; 205 206 for (i = n - 1; i >= 0; i--) { 207 struct ir3_instruction *instr = input[i]; 208 if (instr) { 209 block = instr->block; 210 } else if (block) { 211 instr = ir3_NOP(block); 212 ir3_reg_create(instr, 0, IR3_REG_SSA); /* dummy dst */ 213 input[i] = instr; 214 mask |= (1 << i); 215 } 216 } 217 218 group_n(&arr_ops_in, input, n); 219 220 for (i = 0; i < n; i++) { 221 if (mask & (1 << i)) 222 input[i] = NULL; 223 } 224} 225 226static void 227find_neighbors(struct ir3 *ir) 228{ 229 unsigned i; 230 231 /* shader inputs/outputs themselves must be contiguous as well: 232 * 233 * NOTE: group inputs first, since we only insert mov's 234 * *before* the conflicted instr (and that would go badly 235 * for inputs). By doing inputs first, we should never 236 * have a conflict on inputs.. pushing any conflict to 237 * resolve to the outputs, for stuff like: 238 * 239 * MOV OUT[n], IN[m].wzyx 240 * 241 * NOTE: we assume here inputs/outputs are grouped in vec4. 242 * This logic won't quite cut it if we don't align smaller 243 * on vec4 boundaries 244 */ 245 for (i = 0; i < ir->ninputs; i += 4) 246 pad_and_group_input(&ir->inputs[i], 4); 247 for (i = 0; i < ir->noutputs; i += 4) 248 group_n(&arr_ops_out, &ir->outputs[i], 4); 249 250 for (i = 0; i < ir->noutputs; i++) { 251 if (ir->outputs[i]) { 252 struct ir3_instruction *instr = ir->outputs[i]; 253 instr_find_neighbors(instr); 254 } 255 } 256 257 list_for_each_entry (struct ir3_block, block, &ir->block_list, node) { 258 for (i = 0; i < block->keeps_count; i++) { 259 struct ir3_instruction *instr = block->keeps[i]; 260 instr_find_neighbors(instr); 261 } 262 263 /* We also need to account for if-condition: */ 264 if (block->condition) 265 instr_find_neighbors(block->condition); 266 } 267} 268 269void 270ir3_group(struct ir3 *ir) 271{ 272 ir3_clear_mark(ir); 273 find_neighbors(ir); 274} 275