ir3_group.c revision b8e80941
1/*
2 * Copyright (C) 2014 Rob Clark <robclark@freedesktop.org>
3 *
4 * Permission is hereby granted, free of charge, to any person obtaining a
5 * copy of this software and associated documentation files (the "Software"),
6 * to deal in the Software without restriction, including without limitation
7 * the rights to use, copy, modify, merge, publish, distribute, sublicense,
8 * and/or sell copies of the Software, and to permit persons to whom the
9 * Software is furnished to do so, subject to the following conditions:
10 *
11 * The above copyright notice and this permission notice (including the next
12 * paragraph) shall be included in all copies or substantial portions of the
13 * Software.
14 *
15 * THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
16 * IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
17 * FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT.  IN NO EVENT SHALL
18 * THE AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
19 * LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
20 * OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE
21 * SOFTWARE.
22 *
23 * Authors:
24 *    Rob Clark <robclark@freedesktop.org>
25 */
26
27#include "ir3.h"
28
29/*
30 * Find/group instruction neighbors:
31 */
32
33/* bleh.. we need to do the same group_n() thing for both inputs/outputs
34 * (where we have a simple instr[] array), and fanin nodes (where we have
35 * an extra indirection via reg->instr).
36 */
37struct group_ops {
38	struct ir3_instruction *(*get)(void *arr, int idx);
39	void (*insert_mov)(void *arr, int idx, struct ir3_instruction *instr);
40};
41
42static struct ir3_instruction *arr_get(void *arr, int idx)
43{
44	return ((struct ir3_instruction **)arr)[idx];
45}
46static void arr_insert_mov_out(void *arr, int idx, struct ir3_instruction *instr)
47{
48	((struct ir3_instruction **)arr)[idx] =
49			ir3_MOV(instr->block, instr, TYPE_F32);
50}
51static void arr_insert_mov_in(void *arr, int idx, struct ir3_instruction *instr)
52{
53	/* so, we can't insert a mov in front of a meta:in.. and the downstream
54	 * instruction already has a pointer to 'instr'.  So we cheat a bit and
55	 * morph the meta:in instruction into a mov and insert a new meta:in
56	 * in front.
57	 */
58	struct ir3_instruction *in;
59
60	debug_assert(instr->regs_count == 1);
61
62	in = ir3_instr_create(instr->block, OPC_META_INPUT);
63	in->inout.block = instr->block;
64	ir3_reg_create(in, instr->regs[0]->num, 0);
65
66	/* create src reg for meta:in and fixup to now be a mov: */
67	ir3_reg_create(instr, 0, IR3_REG_SSA)->instr = in;
68	instr->opc = OPC_MOV;
69	instr->cat1.src_type = TYPE_F32;
70	instr->cat1.dst_type = TYPE_F32;
71
72	((struct ir3_instruction **)arr)[idx] = in;
73}
74static struct group_ops arr_ops_out = { arr_get, arr_insert_mov_out };
75static struct group_ops arr_ops_in = { arr_get, arr_insert_mov_in };
76
77static struct ir3_instruction *instr_get(void *arr, int idx)
78{
79	return ssa(((struct ir3_instruction *)arr)->regs[idx+1]);
80}
81static void
82instr_insert_mov(void *arr, int idx, struct ir3_instruction *instr)
83{
84	((struct ir3_instruction *)arr)->regs[idx+1]->instr =
85			ir3_MOV(instr->block, instr, TYPE_F32);
86}
87static struct group_ops instr_ops = { instr_get, instr_insert_mov };
88
89/* verify that cur != instr, but cur is also not in instr's neighbor-list: */
90static bool
91in_neighbor_list(struct ir3_instruction *instr, struct ir3_instruction *cur, int pos)
92{
93	int idx = 0;
94
95	if (!instr)
96		return false;
97
98	if (instr == cur)
99		return true;
100
101	for (instr = ir3_neighbor_first(instr); instr; instr = instr->cp.right)
102		if ((idx++ != pos) && (instr == cur))
103			return true;
104
105	return false;
106}
107
108static void
109group_n(struct group_ops *ops, void *arr, unsigned n)
110{
111	unsigned i, j;
112
113	/* first pass, figure out what has conflicts and needs a mov
114	 * inserted.  Do this up front, before starting to setup
115	 * left/right neighbor pointers.  Trying to do it in a single
116	 * pass could result in a situation where we can't even setup
117	 * the mov's right neighbor ptr if the next instr also needs
118	 * a mov.
119	 */
120restart:
121	for (i = 0; i < n; i++) {
122		struct ir3_instruction *instr = ops->get(arr, i);
123		if (instr) {
124			struct ir3_instruction *left = (i > 0) ? ops->get(arr, i - 1) : NULL;
125			struct ir3_instruction *right = (i < (n-1)) ? ops->get(arr, i + 1) : NULL;
126			bool conflict;
127
128			/* check for left/right neighbor conflicts: */
129			conflict = conflicts(instr->cp.left, left) ||
130				conflicts(instr->cp.right, right);
131
132			/* Mixing array elements and higher register classes
133			 * (ie. groups) doesn't really work out in RA.  See:
134			 *
135			 * https://trello.com/c/DqeDkeVf/156-bug-with-stk-70frag
136			 */
137			if (instr->regs[0]->flags & IR3_REG_ARRAY)
138				conflict = true;
139
140			/* we also can't have an instr twice in the group: */
141			for (j = i + 1; (j < n) && !conflict; j++)
142				if (in_neighbor_list(ops->get(arr, j), instr, i))
143					conflict = true;
144
145			if (conflict) {
146				ops->insert_mov(arr, i, instr);
147				/* inserting the mov may have caused a conflict
148				 * against the previous:
149				 */
150				goto restart;
151			}
152		}
153	}
154
155	/* second pass, now that we've inserted mov's, fixup left/right
156	 * neighbors.  This is guaranteed to succeed, since by definition
157	 * the newly inserted mov's cannot conflict with anything.
158	 */
159	for (i = 0; i < n; i++) {
160		struct ir3_instruction *instr = ops->get(arr, i);
161		if (instr) {
162			struct ir3_instruction *left = (i > 0) ? ops->get(arr, i - 1) : NULL;
163			struct ir3_instruction *right = (i < (n-1)) ? ops->get(arr, i + 1) : NULL;
164
165			debug_assert(!conflicts(instr->cp.left, left));
166			if (left) {
167				instr->cp.left_cnt++;
168				instr->cp.left = left;
169			}
170
171			debug_assert(!conflicts(instr->cp.right, right));
172			if (right) {
173				instr->cp.right_cnt++;
174				instr->cp.right = right;
175			}
176		}
177	}
178}
179
180static void
181instr_find_neighbors(struct ir3_instruction *instr)
182{
183	struct ir3_instruction *src;
184
185	if (ir3_instr_check_mark(instr))
186		return;
187
188	if (instr->opc == OPC_META_FI)
189		group_n(&instr_ops, instr, instr->regs_count - 1);
190
191	foreach_ssa_src(src, instr)
192		instr_find_neighbors(src);
193}
194
195/* a bit of sadness.. we can't have "holes" in inputs from PoV of
196 * register assignment, they still need to be grouped together.  So
197 * we need to insert dummy/padding instruction for grouping, and
198 * then take it back out again before anyone notices.
199 */
200static void
201pad_and_group_input(struct ir3_instruction **input, unsigned n)
202{
203	int i, mask = 0;
204	struct ir3_block *block = NULL;
205
206	for (i = n - 1; i >= 0; i--) {
207		struct ir3_instruction *instr = input[i];
208		if (instr) {
209			block = instr->block;
210		} else if (block) {
211			instr = ir3_NOP(block);
212			ir3_reg_create(instr, 0, IR3_REG_SSA);    /* dummy dst */
213			input[i] = instr;
214			mask |= (1 << i);
215		}
216	}
217
218	group_n(&arr_ops_in, input, n);
219
220	for (i = 0; i < n; i++) {
221		if (mask & (1 << i))
222			input[i] = NULL;
223	}
224}
225
226static void
227find_neighbors(struct ir3 *ir)
228{
229	unsigned i;
230
231	/* shader inputs/outputs themselves must be contiguous as well:
232	 *
233	 * NOTE: group inputs first, since we only insert mov's
234	 * *before* the conflicted instr (and that would go badly
235	 * for inputs).  By doing inputs first, we should never
236	 * have a conflict on inputs.. pushing any conflict to
237	 * resolve to the outputs, for stuff like:
238	 *
239	 *     MOV OUT[n], IN[m].wzyx
240	 *
241	 * NOTE: we assume here inputs/outputs are grouped in vec4.
242	 * This logic won't quite cut it if we don't align smaller
243	 * on vec4 boundaries
244	 */
245	for (i = 0; i < ir->ninputs; i += 4)
246		pad_and_group_input(&ir->inputs[i], 4);
247	for (i = 0; i < ir->noutputs; i += 4)
248		group_n(&arr_ops_out, &ir->outputs[i], 4);
249
250	for (i = 0; i < ir->noutputs; i++) {
251		if (ir->outputs[i]) {
252			struct ir3_instruction *instr = ir->outputs[i];
253			instr_find_neighbors(instr);
254		}
255	}
256
257	list_for_each_entry (struct ir3_block, block, &ir->block_list, node) {
258		for (i = 0; i < block->keeps_count; i++) {
259			struct ir3_instruction *instr = block->keeps[i];
260			instr_find_neighbors(instr);
261		}
262
263		/* We also need to account for if-condition: */
264		if (block->condition)
265			instr_find_neighbors(block->condition);
266	}
267}
268
269void
270ir3_group(struct ir3 *ir)
271{
272	ir3_clear_mark(ir);
273	find_neighbors(ir);
274}
275