Lines Matching defs:i0
149 * representation is "union"ed with 32 bit values "i0" and "i1", and, on
158 * first byte to be the LSB of i0. We cannot have both these things, so we
161 * 64-bit datatype since the relative order of i0 and i1 are unknown. It
232 int32_t i0;
250 rslt = (cvt.b32.i0 & 0x3f3f3f3fL) << 2; \
257 #define LOAD(d,d0,d1,bl) d0 = (bl).b32.i0, d1 = (bl).b32.i1
259 #define OR(d,d0,d1,bl) d0 |= (bl).b32.i0, d1 |= (bl).b32.i1
260 #define STORE(s,s0,s1,bl) (bl).b32.i0 = s0, (bl).b32.i1 = s1
813 B.b32.i0 = k ^ q0 ^ kp->b32.i0; \
Indexes created Sat Sep 20 22:09:52 GMT 2025