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      1 /* Split a symbol name.
      2 
      3    Copyright (C) 2022-2024 Free Software Foundation, Inc.
      4 
      5    This file is part of GDB.
      6 
      7    This program is free software; you can redistribute it and/or modify
      8    it under the terms of the GNU General Public License as published by
      9    the Free Software Foundation; either version 3 of the License, or
     10    (at your option) any later version.
     11 
     12    This program is distributed in the hope that it will be useful,
     13    but WITHOUT ANY WARRANTY; without even the implied warranty of
     14    MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
     15    GNU General Public License for more details.
     16 
     17    You should have received a copy of the GNU General Public License
     18    along with this program.  If not, see <http://www.gnu.org/licenses/>.  */
     19 
     20 #include "split-name.h"
     21 #include "cp-support.h"
     22 
     23 /* See split-name.h.  */
     24 
     25 std::vector<std::string_view>
     26 split_name (const char *name, split_style style)
     27 {
     28   std::vector<std::string_view> result;
     29   unsigned int previous_len = 0;
     30 
     31   switch (style)
     32     {
     33     case split_style::CXX:
     34       for (unsigned int current_len = cp_find_first_component (name);
     35 	   name[current_len] != '\0';
     36 	   current_len += cp_find_first_component (name + current_len))
     37 	{
     38 	  gdb_assert (name[current_len] == ':');
     39 	  result.emplace_back (&name[previous_len],
     40 			       current_len - previous_len);
     41 	  /* Skip the '::'.  */
     42 	  current_len += 2;
     43 	  previous_len = current_len;
     44 	}
     45       break;
     46 
     47     case split_style::DOT_STYLE:
     48       /* D and Go-style names.  */
     49       for (const char *iter = strchr (name, '.');
     50 	   iter != nullptr;
     51 	   iter = strchr (iter, '.'))
     52 	{
     53 	  result.emplace_back (&name[previous_len],
     54 			       iter - &name[previous_len]);
     55 	  ++iter;
     56 	  previous_len = iter - name;
     57 	}
     58       break;
     59 
     60     default:
     61       break;
     62     }
     63 
     64   result.emplace_back (&name[previous_len]);
     65   return result;
     66 }
     67 
     68